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- A cigarette company wants to promoe thne sales of X's cigarettes (Brand) with special advertising campaign. Fifty out of every thousand cigarettes are rolled up in gold foil and randomly mixed with the regular (special king-sized, mentholated) cigarettes. The company offers to trade a new package of cigarettes for each gold cigarette a smoker finds in a package of Brand X. What is the probability that buyers of Brand X will find X = 0, 1, 2, 3, . gold cigarettes in a single package of 10 ? ...3. Let X be the random variable that takes on the integers {0, 1, 2, ..., 15} with equal probabilities. Define a new random variable Y = X + A, where A is a random variable that takes on the values {-1, 0, 1} with equal probabilities. If the RVs X and A are independent, find the mutual information between X and Y.I was wondering if you could help me understand how to find the probability of failure of the entire deck system assuming that the failures of groups A, B and C are independent of each other and that the failures of sub-groups B1 and B2 are also independent of each other
- Let X and Y be two random variables such that Cov(X.Y) = -3 . Then %3D O None of these O cov(-3X+5,-3Y+5)=-18 cov(3X+5,-2Y+5)=18 O cov(5X+3,-2Y-2)=-20Suppose that X is a N(3,4) random variable and suppose that Y=5X+2. Determine P(Y>18.5).. Assume that the box contains balls numbered from 1 through 28, and that 3 are selected. A random variable X is defined as 3 times the number of odd balls selected, plus 4 times the number of even. How many different values are possible for the random variable X?
- A platter contains 48 doughnuts: 26 cake, 13 glazed, and nine jelly-filled. Suppose two doughnuts are randomly selected in succession without replacement. Find the probability (to 4 decimal places) of selecting two cake doughnuts. A. 0.0691 B. 0.2881 C. 0.2934 D. 0.5417Q. 1 Deal two cards from a well-shuffled deck of cards. Let the random variable X be the number of aces dealt and let the random variable Y be the number of face cards dealt. (i) Find and sketch fx.y (x, y).An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let R be the random variable counting the number of heads in each outcome. For example, if the outcome is ttt, then R(ttt) = 0. Suppose that the random variable X is defined in terms of R as follows: X= 2R- 4R-4. The values of X are given in the table below. Outcome ttt tth hht thh tht hhh htthth Value of X -4 -6 -4 -4 -6 -4 Calculate the values of the probability distribution function of X, i.e. the function py. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value x of X Px (x) olo