As a result of contamination by atmospheric carbon dioxide, a sodium hydroxide solution contains a small amount of sodium carbonate. To reach the phenolphthalein end point, a 25.00-mL aliquot requires 27.75 mL of 0.1021 M HCl and an additional 1.61 mL to reach the methyl red end point. Calculate the molar concentration of NaOH in the solution.

Q: What mass of KHP will be completely neutralized by 32.57 cm33 of 0.175 M standard NaOH solution? The…

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Q: A sample of vinegar is to be analyzed for its acetic acid content. A volume of 50.0 mL is measured…

A: The volume of 1000.0 mL is equal to 1.0 L. The number of moles of NaOH or OH- in the 31.66 mL of…

Q: Calculate the molar mass of the unknown acid. Be sure your answer has the correct number of…

A: We calculate normality of acid and base then use this formula N1V1 = N2V2

Q: An aqueous sample of 25.0 mL H2SO4 is neutralized by the addition of 28.9 mL of 0.203 M KOH.  What…

A: The neutralisation reaction taking place will be 2 KOH + H2SO4 ------> K2SO4 + 2 H2O

Q: An experiment is carried out by titrating 31.8 mL of a 0.340 M potassium hydroxide solution with…

A: Reaction involved is : KOH + HBr ---> H2O + KBr Volume of KOH = 31.8 ml  Molarity of KOH = 0.340…

Q: An environmental chemist analyzed the effluent (the released waste material) from an industrial…

A: Given :  Volume of sample = 3.52 ml  Volume of NaOH solution = 10.59 ml  Concentration of NaOH…

Q: An impure sample of potassium hydrogen phthalate (KHP) was titrated to determine the percent…

A: We will use stoichiometry of the reaction to get the answer.

Q: A chemistry student weighs out 0.113 g of ascorbic acid (H2C6H,06), a diprotic acid, into a 250. mL…

A: The mass of ascorbic acid is given as 0.113 g and the volume is 250 mL To calculate the volume of…

Q: Titration of a 25.00 mL sample of acid rain required 12.4 mL of 0.009879 M NaOH to reach the end…

A: Volume of sulphuric acid,V1 = 25.00mL Volume of NaOH,V2 = 12.4mL Concentration of NaOH,M2 =…

Q: What mass of hydrogen gas can be produced when a 7.35 g chunk of zinc dissolves in 500. mL of 1.200…

A: Given :-  Mass of Zn = 7.35 g  Molarity of HCl solution = 1.200 M  Volume of HCl solution = 500. mL…

Q: To determine the concentration of a solution of sulfurous acid, a 150.0-mL sample is placed in a…

A: The balanced equation for the titration is,2KOH + H2SO3 → 2H2O + K2SO3Mole of KOH= 0.1463 M ×…

Q: A 16.24 mL sample of dilute H3PO4 requires 40.52 of 0.108 M NaOH for complete neutralization.…

A: The reaction taking place is  3 NaOH + H3PO4 ----> Na3PO4 + 3 H2O Hence from the above reaction…

Q: An acid-base titration is used to standardize a solution of NaOH. A student adds 25.00 mL of a…

A: KHP + NaOH→NaKP + H2O At equivalence point No. of moles of KHP=No. of moles of NaOH

Q: n the titration of a solution of Sodium hydroxide, an acid titrant was prepared by diluting 100.0 mL…

A: Given:Volume of nitric acid=100.0mLmolarity of nitric acid =2.00mol/LFinal volume of the solution…

Q: A chemistry student weighs out 0.166 g of ascorbic acid (H,C,H,O), a diprotic acid, into a 250. mL…

A: Ascorbic acid reacts with sodium hydroxide to form sodium ascorbate and water. The equation for the…

Q: A 0.5504-g sample of KHP (potassium hydrogen phthalate, KHC8H4O4; molar mass = 204.22 g/mol) is…

A:

Q: To determine the concentration of a solution of sulfurous acid, a 50.00-mL sample is placed in a…

A: According to volumetric principleMa*Va = Mb*Vb(The a and b representing the acid and base,…

Q: 6. A buffer is prepared by adding 20.0 g of sodium acetate (CH3COONa) to 500 mL of a 0.150 M acetic…

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Q: Calculate the molarity of an acetic acid solution if 34.57 mL of this solution is needed to…

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Q: A 1.054-g sample of KHP (potassium hydrogen phthalate, KHC3H404; molar mass = 204.22 g/mol) is…

A: Molarity of a solution is the number of moles of solute upon the volume of the solution in liters.…

Q: An analytical chemist weighs out 0.318 g of an unknown triprotic acid into a 250 mL volumetric flask…

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Q: A student performs a titration by filling the titrator with 0.75 M NaOH, and filling a beaker with…

A: Given data: Concentration of NaOH solution: 0.75 M, Volume of NaOH solution: 4.5 mL = 0.0045 L,…

Q: A sodium hydroxide solution contains a small amount of sodium carbonate as a result of contamination…

A: When Phenolphthalein is used as indicator: NaOH is completely neutralised but Na₂CO3 iS Converted…

Q: An unknown potassium hydroxide solution is titrated with a standardized solution of hydrochloric…

A: Molarity equation It is the titration formula used in titration of analyte and titrant that are in…

Q: A 45.15 mL sample of phosphoric acid required 215mL of 1.000 M sodium hydroxide to reach the…

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Q: A chemistry student weighs out 0.0827 g of phosphoric acid (H,PO,), a triprotic acid, into a 250. mL…

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Q: KHP (potassium hydrogen phthalate, KHC8H4O4

A: Molarity = Moles of solute/ volume of solution (in L) Moles = Mass in gm/molar mass

Q: In a titration experiment, a solution of rubidium hydroxide (RBOH) of unknown concentration was…

A:

Q: titration of 25.00 mL of an unknown HCl solution with 0.1550 M NaOH starts at a buret reading of…

A: We have to find molarity of HCl solution

Q: The phosphoric acid in a 100.00 mL sample of soda was titrated with 0.1025 M NaOH. The first…

A: Firstly calculate the number of millimoles of phosphate ion at third equivalence point.

Q: A chemistry student weighs out 0.106 g of ascorbic acid (H,C,H,O.), a diprotic acid, into a 250. mL…

A:

Q: The titration of 0.314 g of potassium hydrogen phthalate (KHP) requires 13.16 mL of a NaOH solution.…

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Q: 5.00 mL of acetic acid required 37.28 mL of 0.0999 M NaOH to be neutralized in a titration.…

A: Volume of acetic acid= 5 ml Volume of NaOH= 37.28ml Concentration of NaOH=0.0999M

Q: A 23.74-mL volume of 0.0981 M NaOH was used to titrate 25.0 mL of a weak monoprotic acid solution to…

A: When acid reacts with a base, it leads to the formation of salt and water. The chemical reaction for…

Q: For a 50.00 mL sample of a citrus beverage to reach the phenolphthalein endpoint, 17.62 mL of…

A: The balanced equation,   H3C6H5O7 + 3 NaOH (aq) --------> Na3C6H5O7 + 3 H2O (aq) At…

Q: A 10.00 mL portion of an HCl solution required 11.01 mL of 0.09883 M NaOH to reach an end point with…

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