Artificial diamonds can be made using high-pressure, high-temperature presses. Suppose an artificial diamond of volume 1.30 x 10-6 m3 is formed under a pressure of 4.70 GPa. Find the change in its volume (in m³) when it is released from the press and brought to atmospheric pressure. Take the diamond's bulk modulus to be B = 194 GPa. (Assume the system is at sea level.)

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### Problem Explanation: Volume Change in Artificial Diamond Due to Pressure Difference

Artificial diamonds can be created by using high-pressure, high-temperature presses. Suppose an artificial diamond with a volume of \(1.30 \times 10^{-6} \, \text{m}^3\) is formed under a pressure of \(4.70 \, \text{GPa}\). 

#### Objective:
Find the change in its volume (\( \Delta V \) in \( \text{m}^3 \)) when it is released from the press and brought to atmospheric pressure. 

#### Given Data:
- Initial volume, \( V = 1.30 \times 10^{-6} \, \text{m}^3 \)
- Pressure under which it is formed, \( P = 4.70 \, \text{GPa} \)
- Bulk modulus of diamond, \( B = 194 \, \text{GPa} \)
- Atmospheric pressure is assumed to be negligible compared to the pressure under which the diamond was formed.

#### Approach to Solution:
1. **Understand Bulk Modulus**: 
   - The bulk modulus \( B \) is a measure of a substance's resistance to uniform compression.
   - It is given by the formula:
     \[
     B = -\frac{\Delta P}{\frac{\Delta V}{V}}
     \]
     Where \( \Delta P \) is the change in pressure and \( \frac{\Delta V}{V} \) is the relative change in volume.

2. **Calculate the Change in Volume**:
   - Rearrange the bulk modulus formula to solve for \( \Delta V \):
     \[
     \frac{\Delta V}{V} = -\frac{\Delta P}{B}
     \]
3. **Substitute Given Values**:
   - \( \Delta P \approx 4.70 \, \text{GPa} \) (since atmospheric pressure is negligible)
   - \( B = 194 \, \text{GPa} \)
   - Calculate \( \frac{\Delta V}{V} \):
     \[
     \frac{\Delta V}{V} = -\frac{4.70}{194}
     \]
     \[
     \frac{\Delta V}{V} = -0.0242
     \]
   - Thus,
     \[
     \Delta V = V
Transcribed Image Text:### Problem Explanation: Volume Change in Artificial Diamond Due to Pressure Difference Artificial diamonds can be created by using high-pressure, high-temperature presses. Suppose an artificial diamond with a volume of \(1.30 \times 10^{-6} \, \text{m}^3\) is formed under a pressure of \(4.70 \, \text{GPa}\). #### Objective: Find the change in its volume (\( \Delta V \) in \( \text{m}^3 \)) when it is released from the press and brought to atmospheric pressure. #### Given Data: - Initial volume, \( V = 1.30 \times 10^{-6} \, \text{m}^3 \) - Pressure under which it is formed, \( P = 4.70 \, \text{GPa} \) - Bulk modulus of diamond, \( B = 194 \, \text{GPa} \) - Atmospheric pressure is assumed to be negligible compared to the pressure under which the diamond was formed. #### Approach to Solution: 1. **Understand Bulk Modulus**: - The bulk modulus \( B \) is a measure of a substance's resistance to uniform compression. - It is given by the formula: \[ B = -\frac{\Delta P}{\frac{\Delta V}{V}} \] Where \( \Delta P \) is the change in pressure and \( \frac{\Delta V}{V} \) is the relative change in volume. 2. **Calculate the Change in Volume**: - Rearrange the bulk modulus formula to solve for \( \Delta V \): \[ \frac{\Delta V}{V} = -\frac{\Delta P}{B} \] 3. **Substitute Given Values**: - \( \Delta P \approx 4.70 \, \text{GPa} \) (since atmospheric pressure is negligible) - \( B = 194 \, \text{GPa} \) - Calculate \( \frac{\Delta V}{V} \): \[ \frac{\Delta V}{V} = -\frac{4.70}{194} \] \[ \frac{\Delta V}{V} = -0.0242 \] - Thus, \[ \Delta V = V
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