How do I find Equilibrium [FeSCN2+] with given values. See image. **Title: Spectrophotometric Analysis of Equilibrium Constants****Table: PART A - Table 1****Concentration of Fe(NO\(_3\))\(_3\) in 0.10 M HNO\(_3\): 4.00E-02** **Concentration of NaSCN in 0.10 M HI:**| Soln (Flask) No. | Flask No. 1 | Flask No. 2 | Flask No. 3 | Flask No. 4 | Flask No. 5 | Flask No. 6 ||------------------|-------------|-------------|-------------|-------------|-------------|-------------|| **Vol of NaSCN Soln (mL)** | 0 | 1 | 2 | 3 | 4 | 5 || **Initial [SCN\(^-\)]** | 0 | 4.00E-05 | 8.00E-05 | 1.20E-04 | 1.60E-04 | 2.00E-04 || **Eqm [FeSCN\(^{2+}\)]** | 0 | | | | | || **Absorbance** | 0.001 | 0.03 | 0.16 | 0.234 | 0.308 | 0.362 |**Explanation:**This table displays data from an experiment designed to explore the relationship between the concentration of reactants and the absorbance of the product at equilibrium in a chemical reaction involving iron(III) nitrate and sodium thiocyanate.- **Flask Number**: Identifies each experimental setup.- **Vol of NaSCN Soln (mL)**: The volume of sodium thiocyanate solution added to each flask.- **Initial [SCN\(^-\)]**: The initial concentration of thiocyanate ions before the reaction reaches equilibrium.- **Eqm [FeSCN\(^{2+}\)]**: The concentration of the complex ion at equilibrium, not provided in this table.- **Absorbance**: The measured absorbance of the solution, which is directly related to the concentration of the FeSCN\(^{2+}\) complex.The data shows a trend of

According to Beer's law, the absorbance for any solution is directly proportional to its initial concentration and path length of the solution. Mathematically, Beer's law can be stated as A =∈Cl Here, A is absorbance, C is concentration, l is the path length of solution (1 cm), ∈is the molar extinction coefficient. Firstly a graph between absorbance and concentration is plotted to calculate the molar extinction coefficient. The slope of the absorbance vs concentration curve is 0.0771. The relation between concentration and absorbance is given as A = ∈Cl So the plot between absorbance and concentration gives the molar extinction coefficient as a slope. For the given data, ∈is 0.0771 M. For flask 1, absorbance is 0.001. So, the final concentration is given as concentration,C = A∈C= 0.0010.0771 M-1= 0.0129 MFor flask 2, absorbance is 0.03. So, the final concentration is given as concentration,C = A∈C= 0.030.0771 M-1= 0.389 MFor flask 3, absorbance is 0.16. So, the final concentration is given as concentration,C = A∈C= 0.160.0771 M-1= 2.075 MFor flask 4, absorbance is 0.234. So, the final concentration is given as concentration,C = A∈C= 0.2340.0771 M-1= 3.035 MFor flask 5, absorbance is 0.303. So, the final concentration is given as concentration,C = A∈C= 0.3030.0771 M-1= 3.929 MFor flask 6, absorbance is 0.362 So, the final concentration is given as concentration,C = A∈C= 0.3620.0771 M-1= 4.695 M