Arrange the following ions in terms of increasing strength as an oxidizing agent. Arrange the three metals in terms of increasing strength as a reducing O Fe2+ < Cu2+ < Zn2+ く agent. O Cu2+ < Zn2+ < Fe2+ Recall: O Fe2+ < Zn2+ < Cu²+ O Cu2+ < Fe2+ < Zn²+ ARALEO - Anode: Reducing Agent Losses Electron, process is called OZn2+ < Fe2+ < Cu²+ Oxidation O Zn2+ < Cu2+< Fe2+ COAGER - Cathode: Oxidizing Agent Gains Electron, process is called Reduction Arrange the three metals in terms of increasing ability to undergo oxidation O Fe < Cu < Zn based on the observations in nails A, C and D. O Fe < Zn < Cu Cu < Zn < Fe O Cu < Fe < Zn Zn < Fe < Cu O Fe < Cu < Zn O Cu < Zn < Fe O Fe < Zn < Cu Zn < Cu < Fe O Zn < Cu < Fe O Zn < Fe < Cu O Cu < Fe < Zn
Arrange the following ions in terms of increasing strength as an oxidizing agent. Arrange the three metals in terms of increasing strength as a reducing O Fe2+ < Cu2+ < Zn2+ く agent. O Cu2+ < Zn2+ < Fe2+ Recall: O Fe2+ < Zn2+ < Cu²+ O Cu2+ < Fe2+ < Zn²+ ARALEO - Anode: Reducing Agent Losses Electron, process is called OZn2+ < Fe2+ < Cu²+ Oxidation O Zn2+ < Cu2+< Fe2+ COAGER - Cathode: Oxidizing Agent Gains Electron, process is called Reduction Arrange the three metals in terms of increasing ability to undergo oxidation O Fe < Cu < Zn based on the observations in nails A, C and D. O Fe < Zn < Cu Cu < Zn < Fe O Cu < Fe < Zn Zn < Fe < Cu O Fe < Cu < Zn O Cu < Zn < Fe O Fe < Zn < Cu Zn < Cu < Fe O Zn < Cu < Fe O Zn < Fe < Cu O Cu < Fe < Zn
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![From the result above, the cell potential
for the corrosion of copper is very low
compared to iron. The
oxidation/corrosion of copper is a LESS
spontaneous reaction compared to the
RESULT FOR NAIL A
oxidation/corrosion of iron. Therefore,
iron
more prone to oxidation
compared to copper. We can say that
iron is a more active metal than copper.
Using the result for Nail C:
From the result above, the cell potential
The added potassium ferricyanide
for the corrosion of Zinc is higher than
iron. The oxidation/corrosion of copper
(Fe(CN)6³) in the agar turns Prussian
blue when it reacts with Fe2+ in the
is a MORE spontaneous reaction
compared to the oxidation/corrosion of
iron. Therefore, zinc is more prone to
solution to produce iron (II)
oxidation compared to iron. We can say
hexacyanoferrate (III):
that zinc is a more active metal than
iron.
Fe 2* (aq)
Fe(CN),³-
(aq)
+
Fez[Fe(CN)6]2 (Prussian blue)
Using the result for Nail D:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcd796b93-72b7-49ed-8d3e-74d395a7d448%2F0800c348-b5a0-4033-990f-c935d96524eb%2Fdbjt8zw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:From the result above, the cell potential
for the corrosion of copper is very low
compared to iron. The
oxidation/corrosion of copper is a LESS
spontaneous reaction compared to the
RESULT FOR NAIL A
oxidation/corrosion of iron. Therefore,
iron
more prone to oxidation
compared to copper. We can say that
iron is a more active metal than copper.
Using the result for Nail C:
From the result above, the cell potential
The added potassium ferricyanide
for the corrosion of Zinc is higher than
iron. The oxidation/corrosion of copper
(Fe(CN)6³) in the agar turns Prussian
blue when it reacts with Fe2+ in the
is a MORE spontaneous reaction
compared to the oxidation/corrosion of
iron. Therefore, zinc is more prone to
solution to produce iron (II)
oxidation compared to iron. We can say
hexacyanoferrate (III):
that zinc is a more active metal than
iron.
Fe 2* (aq)
Fe(CN),³-
(aq)
+
Fez[Fe(CN)6]2 (Prussian blue)
Using the result for Nail D:

Transcribed Image Text:Arrange the following ions in terms of
increasing strength as an oxidizing
agent.
Arrange the three metals in terms
of increasing strength as a reducing
O Fe2+ < Cu²+ < Zn²+
agent.
Cu2+ < Zn²+ < Fe2+
Recall:
O Fe2+ < Zn²+ < Cu²+
O Cu²+ < Fe2+ < Zn²+
ARALEO - Anode: Reducing Agent
Losses Electron, process is called
O Zn²+ < Fe²+ < Cu²+
Oxidation
O Zn2+ < Cu2+< Fe2+
COAGER - Cathode: Oxidizing Agent
Gains Electron, process is called
Reduction
Arrange the three metals in terms of
increasing ability to undergo oxidation
O Fe < Cu < Zn
based on the observations in nails A, C
and D.
O Fe < Zn < Cu
O Cu < Zn < Fe
O Cu < Fe < Zn
O Zn < Fe < Cu
く
O Fe < Cu < Zn
O Cu < Zn < Fe
O Fe < Zn < Cu
O Zn < Cu < Fe
O Zn < Cu < Fe
O Zn < Fe < Cụ
O Cu < Fe < Zn
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