Area in the grey can not be edited. Meaning line 1(or beinging of code)-line6 and from line 8 - 8 (or end of code).   Code must be inbetween the two blocks of Java Code.    Note: Character.isLetter() returns true if a character is a letter, and false otherwise. Ex: Character.isLetter('a') returns true. Character.isLetter('8') returns false.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Area in the grey can not be edited. Meaning line 1(or beinging of code)-line6 and from line 8 - 8 (or end of code).   Code must be inbetween the two blocks of Java Code. 

 

Note: Character.isLetter() returns true if a character is a letter, and false otherwise. Ex: Character.isLetter('a') returns true. Character.isLetter('8') returns false.

 
Jump to level 1
Declare a Boolean variable named goodPasswd. Use goodPasswd to output "Valid" if secretStr contains fewer than 5 letters and
secretStr's length is greater than 5. Otherwise, output "Invalid".
Ex: If the input is 3yg4tz, then the output is:
Valid
Ex: If the input is 9kwdM, then the output is:
Invalid
Note: Character.isLetter()) returns true if a character is a letter, and false otherwise. Ex: Character.isLetter('a') returns true.
Character.isLetter('8') returns false.
1 import java.util.Scanner;
2
3 public class ValidInvalid {
4
5
6
7
.89 1000BM5
11
public static void main(String[] args) {
Scanner scnr = new Scanner (System.in);
String secretStr;
12
13
14 }
15}
if (goodPasswd) {
System.out.println("Valid");
}
else {
}
System.out.println("Invalid");
Transcribed Image Text:Jump to level 1 Declare a Boolean variable named goodPasswd. Use goodPasswd to output "Valid" if secretStr contains fewer than 5 letters and secretStr's length is greater than 5. Otherwise, output "Invalid". Ex: If the input is 3yg4tz, then the output is: Valid Ex: If the input is 9kwdM, then the output is: Invalid Note: Character.isLetter()) returns true if a character is a letter, and false otherwise. Ex: Character.isLetter('a') returns true. Character.isLetter('8') returns false. 1 import java.util.Scanner; 2 3 public class ValidInvalid { 4 5 6 7 .89 1000BM5 11 public static void main(String[] args) { Scanner scnr = new Scanner (System.in); String secretStr; 12 13 14 } 15} if (goodPasswd) { System.out.println("Valid"); } else { } System.out.println("Invalid");
Expert Solution
Step 1: Algorithm

1. Import Scanner class
2. Create a Scanner object (scnr) to read input
3. Declare a String variable (secretStr)
4. Read input from the user and store it in secretStr
5. Close the Scanner object
6. Initialize letterCount to 0
7. For each character 'c' in secretStr:
   a. If 'c' is a letter, increment letterCount by 1
8. Initialize goodPasswd based on the condition (letterCount < 5) && (length of secretStr > 5)
9. If goodPasswd is true, print "Valid"
   Else, print "Invalid"

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