Are any of these results significant? ### Analysis of Variance (ANOVA) - Intended Screen TimeThis table presents an ANOVA summary for the analysis of intended screen time. The purpose of this analysis is to determine if there are statistically significant differences between groups based on the variables analyzed. Below is a detailed explanation of each component of the table:| Source | Sum of Squares | df | Mean Square | F | p | η² ||-------------------------|----------------|----|-------------|---------|-------|------|| **Reference Group** | 0.0307 | 1 | 0.0307 | 0.0216 | 0.884 | 0.000 || **Norm** | 3.4376 | 1 | 3.4376 | 2.4202 | 0.124 | 0.029 || **Reference Group ⨯ Norm** | 1.7006 | 1 | 1.7006 | 1.1973 | 0.277 | 0.014 || **Residuals** | 112.2100 | 79 | 1.4204 | | | |#### Explanation of Terms:- **Sum of Squares**: This represents the total variation attributed to each factor.- **df (Degrees of Freedom)**: This indicates the number of values that are free to vary for each source of variation.- **Mean Square**: Calculated as the sum of squares divided by the degrees of freedom, indicating the average variation.- **F**: The F-statistic, which is used to assess whether there are any significant differences between the means of the groups.- **p (p-value)**: This value indicates the probability of observing the data, assuming that the null hypothesis is true. A lower p-value (typically < 0.05) suggests significant differences.- **η² (Eta Squared)**: This is a measure of the effect size, indicating the proportion of the total variance that is attributed to an effect.#### Interpretation:- The **Reference Group** factor contributes minimally to the variation in intended screen time as indicated by the very low F-value and non-significant p-value (0.884).- The **Norm** factor shows a larger contribution to variance, but it is not statistically significant with a p-value of 0

The ANOVA table for Intended Screen Time is given.

Answered: Are any of these results significant?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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QUESTION 4 PART A- What is the standard error of the correlation coefficient for the association of extroversion and neuroticism in personalities? QUESTION 4 PART B- Carry out a formal t-test for the association between extroversion and neuroticism in personalities.xls. H0: The population correlation coefficient is 0. HA: The population correlation coefficient is not 0. What is the value of the t-statistic corresponding to this test? (Report the absolute value. The t-distribution is symmetric, thus it is easier to compare the absolute value of the t-statistic with the positive values in statistical table C). DATA IS ATTACHED.
Managers of an outdoor coffee stand in Coast City are examining the relationship between (hot) coffee sales and daily temperature, hoping to be able to predict a day's total coffee sales from the maximum temperature that day. The bivariate data values for the coffee sales (denoted by y , in dollars) and the maximum temperature (denoted by x , in degrees Fahrenheit) for each of fifteen randomly selected days during the past year are given below. These data are plotted in the scatter plot in Figure 1. Temperature, x(in degrees Fahrenheit) Coffee sales, y(in dollars) 53.1 2215.5 76.6 1982.7 70.1 1937.3 39.7 2251.1 72.5 1603.9 48.4 2024.2 46.7 2135.3 83.9 1536.5 58.4 1965.6 38.5 1944.3 68.2 1746.1 75.4 1472.1 65.6 1819.5 53.9 1627.4 45.1 1782.3 Send data to calculator Send data to Excel Coffee sales(in dollars) y 1200 1400 1600 1800 2000 2200 2400 x 40 50 60 70 80 90…
a) Compute the value of the sample correlation coefficient, r. (Round your answer to four decimal places.) r = b) Calculate the test statistic and determine the P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.) t = P- value = c) If a regression analysis were to be carried out to predict endurance from lactate level, what proportion of observed variation in endurance could be attributed to the approximate linear relationship? Answer the question without doing any regression calculations. (Round your answer to four decimal places.) ____________ d) If a regression analysis were to be carried out to predict lactate level from endurance, what proportion of observed variation in endurance could be attributed to the approximate linear relationship? Answer the question without doing any regression calculations. (Round your answer to four decimal places.) _____________
Question 1. Greater than or Less than. Question 2. IS or IS NOT.
Managers of an outdoor coffee stand in Coast City are examining the relationship between (hot) coffee sales and daily temperature, hoping to be able to predict a day's total coffee sales from the maximum temperature that day. The bivariate data values for the coffee sales (denoted by y, in dollars) and the maximum temperature (denoted by x, in degrees Fahrenheit) for each of sixteen randomly selected days during the past year are given below. These data are plotted in the scatter plot in Figure 1. Temperature, x (in degrees Fahrenheit) Coffee sales, y (in dollars) 71.5 1970.9 58.7 1953.9 53.7 1791.1 2400+ 83.0 1570.3 2200+ 62.8 1852.7 74.6 1633.6 2000- ** 40.4 1973.9 1800- 51.5 2250.9 44.6 1808.5 1600- 45.5 1977.3 1400- 45.6 2190.5 1200 69.4 1789.1 55.0 1598.2 50 70 80 90 40.6 2272.0 74.0 1937.0 Figure 1 76.6 1547.1 Send data to Excel Continue Submit Assignment O 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use Privacy Accessibility here to search 99+ 5 4.
Give answer from the choice and explain it as given in image. Note:hand written solution not allowed.
Question 2 A researcher was interested in studying if there is a significant relationship between the severity of COVID 19 and blood types of individuals. 2400 individuals were studied and the results are shown below. Condition Blood Type Blood Type Blood Type Blood Type Blood Type O A B AB Total Critical 64.00 44 20 8 136 Severe 175.00 129 50 15 369 Moderate 211.00 528 151 125 1015 Mild 200.00 400 140 140 880 Total 650.00 1101 361 288 2400 State both the null and alternative hypotheses. Provide the decision rule for making this decision. Use an alpha level of 5%.
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