- arctan(e**) dx =? 1+e2kx A) (arctan(e*)In [cos(arctan(e*)| + S In [cos(arctan(e*)da]+ c kekz B) (arctan(e*")In |cos arctan(ek*)) - S In sin(arctan(ek*) dx + kekr c C) arctan(e*")in |sin(arctan(e*)| - S in sin(arctan(et") e kx kekr 1+e2kx D) (arctan(e*)In |sin(arctan(e*)| + S In |sin(arctan(e*) d] +c kekx 1+e2kx
- arctan(e**) dx =? 1+e2kx A) (arctan(e*)In [cos(arctan(e*)| + S In [cos(arctan(e*)da]+ c kekz B) (arctan(e*")In |cos arctan(ek*)) - S In sin(arctan(ek*) dx + kekr c C) arctan(e*")in |sin(arctan(e*)| - S in sin(arctan(et") e kx kekr 1+e2kx D) (arctan(e*)In |sin(arctan(e*)| + S In |sin(arctan(e*) d] +c kekx 1+e2kx
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![· arctan(ek*)
dx =?
1+e2kx
A) arctan(ek")In|cos(arctan(e*))| + S In |cos(arctan(e**) dx
kekx
1+e2kr
B) (arctan(e**)In |cos(arctan(ek*)| - S In |sin(arctan(ek*))|
kekx
+ [xp²
C) arctan(e*) In |sin(arctan(e**)| - SIn sin( arctan(e**)) dx] + c
ke kr
1+e2kx
D) [arctan(e**)In|stn(arctan(e**))| + S In |sin(arctan(e*")
kek*
dx + c
E) (arctan(e*)In |stn(arctan(e**)| - S in|cos(arctan(e*)| de] +c
kekx
1+e](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fab1bcc26-5e04-4121-961d-ef4ab47e2782%2Fc200376e-a1f7-46a2-8d87-0a45c75dd729%2F7tbljk_processed.png&w=3840&q=75)
Transcribed Image Text:· arctan(ek*)
dx =?
1+e2kx
A) arctan(ek")In|cos(arctan(e*))| + S In |cos(arctan(e**) dx
kekx
1+e2kr
B) (arctan(e**)In |cos(arctan(ek*)| - S In |sin(arctan(ek*))|
kekx
+ [xp²
C) arctan(e*) In |sin(arctan(e**)| - SIn sin( arctan(e**)) dx] + c
ke kr
1+e2kx
D) [arctan(e**)In|stn(arctan(e**))| + S In |sin(arctan(e*")
kek*
dx + c
E) (arctan(e*)In |stn(arctan(e**)| - S in|cos(arctan(e*)| de] +c
kekx
1+e
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