(arctan o tan)' = 1 – pi k E z°(k +1/2)pi When differentiating on the Real line is this true?
(arctan o tan)' = 1 – pi k E z°(k +1/2)pi When differentiating on the Real line is this true?
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.5: Trigonometric Graphs
Problem 6E
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![(arctan o tan)' = 1 – pi ke 2°(k + 1/2)pi
When differentiating on the Real line is this true?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2a69bf48-7e74-4979-9ac6-8baafdb7988f%2F561eb0d6-1939-479c-b3c8-9f5bbe34645d%2Fy2bmgtl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(arctan o tan)' = 1 – pi ke 2°(k + 1/2)pi
When differentiating on the Real line is this true?
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