Arandom sample of 40 adults with no chidren under the age of 18 years resuts in a mean dally leisure time of 5.55 houn, with a standard deviation of 234 hours Arandom sample of 40 aduts with children under the age of 18 results in a mean daily leisure time of 444 hours, with a slandard deviation of 163 hours Constuctand interpret a 95% confidence interval for the mean diference in leisure tine between adut with no chidren and adts with chidren (P)Let , represent the mean leisure hours of adults with no children under the age of 18 and pi epresent the mean tetsure hours of aduts with child en under the ageof 18The 99% confidence iterval for (-2) is the range trom 2 hours to (9) hours(Round to tero decimal places an meeded)Enter your answer in the edt fields and then dick Check Answec

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Description: Arandom sample of 40 adults with no chidren under the age of 18 years resuts in a mean dally leisure time of 5.55 houn, with a standard deviation of 234 hours Arandom sample of 40 aduts with children under the age of 18 results in a mean daily leisu

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Arandom sample of 40 aduts with no chidren under the age of 18 years resus in a nean dally lesure tire of 5.55 hour, with a standard devialion of 234 hours A random sample of 40 aduts with children under the age of 18 esults in a mean daly leisure time of 4 44 and interpreta 95% confidence interval for the mean diference in leiure tie behween aduts with no chidren and with a slandard deviation of 163 hours Construct Soen (P) Let , represent the mean leisure hours of adults with no children under the age of 18 and p present the mean fesure hours of aduti with childn under the age of 18 The 95% contidence interval for ( ) sthe ange from 2 hours tohours (Round to teo decimal places an needed)

Arandom sample of 40 aduts with no chidren under the age of 18 years resus in a nean dally lesure tire of 5.55 hour, with a standard devialion of 234 hours A random sample of 40 aduts with children under the age of 18 esults in a mean daly leisure time of 4 44 and interpreta 95% confidence interval for the mean diference in leiure tie behween aduts with no chidren and with a slandard deviation of 163 hours Construct Soen (P) Let , represent the mean leisure hours of adults with no children under the age of 18 and p present the mean fesure hours of aduti with childn under the age of 18 The 95% contidence interval for ( ) sthe ange from 2 hours tohours (Round to teo decimal places an needed)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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