I am lost on how to use the "if_name_=='_main_':" to solve this problem. I'm stuck after line 10. A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate aroundthe sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a yearhas 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:1) The year must be divisible by 42) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400Some example leap years are 1600, 1712, and 2016.Write a function is_leap_year that will return True if the year is a leap year and False otherwise.Write a program that takes in a year, uses the function to determine whether that year is a leap year, and printsthe response, like given below.Ex: If the input is:1712the output is:1712 is a leap year.Ex: If the input is:1913the output is:1913 is not a leap year.Your program must define and call the following function. The function should return True if the input year is aleap year or False otherwise.def is_leap_year(user_year)TroubleshootingIf your function is failing the tests and is saying that it "did not return a value. Your function may be missing areturn statement", then go back to the lab instructions and check -- what is the function supposed to return andunder which conditions.Note that your code can have more than one return statement in it, since you might need to return differentvalues, depending on the condition. 1 # Define your function here.2 def is_leap_year (user_year):if (year%400==0):34return Trueelif year % 100 == 0:return False7elif year%4==0:8return Trueelse:10return False1112 if== ' _main_':name1314# Type your code here. Your code must call the function.

ar in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longe sun. To account for the difference in time, every 4 years, a leap year takes place. A leap yea 366 days: An extra day, February 29th. The requirements for a given year to be a leap year he year must be divisible by 4 the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 ne example leap years are 1600, 1712, and 2016. ea function is lean vear that will return True if the vear is a lean vear and False othery

ar in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longe sun. To account for the difference in time, every 4 years, a leap year takes place. A leap yea 366 days: An extra day, February 29th. The requirements for a given year to be a leap year he year must be divisible by 4 the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 ne example leap years are 1600, 1712, and 2016. ea function is lean vear that will return True if the vear is a lean vear and False othery

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter6: User-defined Functions

Section: Chapter Questions

Problem 14PE

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in coral language A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. If the input is 1712, the output is: 1712 is a leap year. If the input is 1913, the output is: 1913 is not a leap year. Your program must define and call a function: Function OutputLeapYear(integer inputYear) returns nothing The function should output whether the input year is a leap year or not.
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 - leap year Ex: If the input is: 1913 the output is: 1913 - not a leap year
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400; therefore, both 1700 and 1800 are not leap years Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is 1712, the output is: 1712 - leap year Ex: If the input is 1913, the output is: 1913 - not a leap year
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 output: 1712 is a leap year. input: 1913 output: 1913 is not a leap year. My Code: def is_leap_year(user_year):if((user_year % 4 == 0 and user_year % 100 != 0) or (user_year % 400 == 0)):print("{} is a leap year.".format(user_year))else:print("{} is not a leap year.".format(user_year))return is_leap_year if __name__ == '__main__':user_year =…
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 output: 1712 is a leap year. input: 1913 output: 1913 is not a leap year. My Code: def is_leap_year(user_year):if (user_year%4 == 0) and (user_year%100 != 0):print('{} is a leap year.'.format(user_year))elif user_year == 0:print('{} is not a leap year.'.format(user_year))elif user_year%400 == 0:print('{} is a leap year.'.format(user_year))else: print('{} is not a leap…
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 is a leap year. Ex: If the input is: 1913 the output is: 1913 is not a leap year. Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.def is_leap_year(user_year) Note: This is a lab from a previous chapter that now requires the use of a function. def…
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 output: 1712 is a leap year. input: 1913 output: 1913 is not a leap year. Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.def is_leap_year(user_year) My Code: def is_leap_year(user_year):if((user_year % 4 == 0 and user_year % 100 != 0) or (user_year % 400 == 0)):print("{} is a leap…
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 output: 1712 is a leap year. input: 1913 output: 1913 is not a leap year. Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.def is_leap_year(user_year) My Code: def is_leap_year(user_year):if((user_year % 4 == 0 and user_year % 100 != 0) or (user_year % 400 == 0)):print("{} is a leap…
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400; therefore, both 1700 and 1800 are not leap years Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is 1712, the output is: 1712 - leap year Ex: If the input is 1913, the output is: 1913 - not a leap year #include <stdio.h> #include <stdbool.h> int main(void) { int inputYear; bool isLeapYear = false; scanf("%d", &inputYear); /* Type your code here. */ return 0; }
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is 1712, the output is a leap year. 1712 Ex: If the input is 1913, the output is: 1913 is not la leap year. Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise. bool IsLeapYear(int userYear) Note: This is a lab from a previous chapter that now requires the use of a function.
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A common year in the modern Gregorian Calendar consists of 365 days. In reality, Earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400; therefore, both 1700 and 1800 are not leap years Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines the number of days in February for that year. Ex: If the input is: 1712 the output is: 1712 has 29 days in February. Ex: If the input is: 1913 the output is: 1913 has 28 days in February. Your program must define and call the following method. The method should return the number of days in February for the input year.public static int daysInFeb(int userYear) A common year in the…