How many grams of baking soda, NaHCO3, are needed to react with 169 mL of stomach acid having an HCl concentration of0.08586 M?The reaction isNaHCO3(aq) + HCI(aq) → NaCl(aq) + CO2(g) + H2O(1).i

Concentration(M) of HCl = 0.08586 M Volume(V) = 169 mL = 0.169 L Moles = M × V = 0.08586 × 0.169 =…

Answered: (aq) + CO2(g) + H2O(I).

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter4: Chemical Reactions In Solution

Section: Chapter Questions

Problem 4.120QE

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