Applying Snell's law at points A, B, and C gives the following equations. 1.40 sin a = 1.60 sin 0, [1] 1.20 sin B = 1.40 sin a [2] [3] 1.03 sin 82 = 1.20 sin B Combining Equations [1], [2], and [3] yields sin 02 = 33.82 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. sin 0,. [4]

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The angles of incidence and refraction at each surface are shown in the diagram below.
n = 1.60
n = 1.40
n = 1.20
ic
n4
| 02
Applying Snell's law at points A, B, and C gives the following equations.
1.40 sin a = 1.60 sin 0,
[1]
1.20 sin B = 1.40 sin a
1.03 sin 02
[2]
1.20 sin B
[3]
Combining Equations [1], [2], and [3] yields
sin 02 = 33.82
Your response differs significantly from the correct answer. Rework your solution from the beginning
and check each step carefully. sin 0,.
[4]
Note that Equation [4] is exactly what Snell's law would yield if the second and third layers of this "sandwich"
were ignored. This will always be true if the surfaces of all the layers are parallel to each other.
Transcribed Image Text:The angles of incidence and refraction at each surface are shown in the diagram below. n = 1.60 n = 1.40 n = 1.20 ic n4 | 02 Applying Snell's law at points A, B, and C gives the following equations. 1.40 sin a = 1.60 sin 0, [1] 1.20 sin B = 1.40 sin a 1.03 sin 02 [2] 1.20 sin B [3] Combining Equations [1], [2], and [3] yields sin 02 = 33.82 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. sin 0,. [4] Note that Equation [4] is exactly what Snell's law would yield if the second and third layers of this "sandwich" were ignored. This will always be true if the surfaces of all the layers are parallel to each other.
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