Apply the rules of current and voltage to the following circuits and use the V-IR equation to work out the missing currents, voltages and resistances as required. Unless stated otherwise, assume all bulbs are identical. DON'T FORGET YOUR UNITS! 1=1+1+11 Remember:Toworkoutresistorsinseries R Total = R1 + R2 + R3 Resistorsinparallel R Total R1 R2 R3 1. 3V A1 = A2 A2 = 0.2A) V1 = V2 = V1 √3 = A1 V2 V3

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The system of resistors shown in figure 1 has an effective resistance of 1.50. Calculate the resistance R of the upper resistor. Figure 1: A system of resistors.

For each of the three simple circuit boards you will need to calculate the total resistance Reg for the entire circuit board by using the measured resistances of each of the resistors, and the equations given to you in the theory section. Then using the applied voltage of 2V, as the theoretical voltage Vth for the entire circuit board you can calculate the theoretical current, ith, for the entire circuit board. Table 1(Resistors in series) R(Q) 310 10 100 200 Req 10Ω 1000 200Ω iex(A) 0.0074 0.0064 0.068 0.0064 0.650 0.0064 1.283 Using the equations for resistors in series calculate the theoretical voltages, and currents for each of the resistors, and the entire circuit. Use the measured values of the resistance in your calculations. Then calculate the % errors. Show work. Vex(V) 2.006 ith(A) Vth(V) % Error i % Error V

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Find the expression for the equivalent resistance of 3 resistors (R1.R2.R3) connected in parallel. Sol. In a parallel connection, voltage drops across the resistors so: Using, Ohm's Law V=1 we derive, that 2 = V2/ I3=V3/ Since, the voltage is the same on all resistors, then V= V = Substituting to the, first equation above, we get the following |= V1/ + V2/ + V3/ So: 1 1 1 + + R2 1. Rea R1 R3

DIFFERENTIAL EQUATION: Electric Circuits. Solve the following problems. Show your complete solution. When a resistance R (ohms) and a capacitance C (farads) are connected in series with an emf E (volts), the current I (amperes) is given by the equation: dI 1 dE +-I = dt C R dt If R = 1000 ohms, C = 5x10-4farad.and I = 10 amperes for t = 0, find the current for t = 1 second and E = 100 volts.

In the schematic below two batteries are in series and drive current through the circuit as shown. The first resistor has a voltage drop AV = 2.8 V, the middle resistor has a resistance of R = 154 Q, and the last resistor has a voltage drop AV2 = 1.6 V. Given these parameters, what is the magnitude of current flowing through the circuit in milli-amps (mA)? Giver your answer to 3 significant figures. %3D AV, 3.0 V 4.5 V ww

Conduc-Thor-s. Thor has two square prism conductors that are made of the same ohmic material and with properties indicated below. Conductor Length | Cross-Section Side Length Alpha L Beta L/2 s/4 Suppose both conductors are subject to the same potential difference AV across their length while keeping their temperatures fixed. Which of the following is the correct relation between the electric currents, Ia and IB, through Alpha and Beta? O A. Ia = 8IB O B. 8Ia = Ig O. Ia = 4I8 O D. 4Ig = Ig Clear my choice

Where V is the voltage in volts (symbol V), I is the current in amperes or amps (symbol A), and R is the resistance in ohms (symbol 2). So the following simple circuit shows a battery and a resistor R: R www Hilt