Apply the loop rule to loop abcdefgha in the figure. E, = 18 V +1 d I2 12 0.5 2 R2 2.5 Q 12 R a 13 6.0 2 R3 1.5Q I3 0.5 Q E2 = 45 V %3D I,R2 + Eq + Iz"1 - I3R3 - Igr2 = Ez = 0 O -IR2 + Eq - I1+ I3R3 + I3r2 + E2 = 0 O -1,R2 + Eq - I1 - I;R3 - I3r2 + E2 = 0 O -I,R2 + E1 - Ir1+ I3R3 + Izr2 - E2 = 0 %3D %3D %3D
Apply the loop rule to loop abcdefgha in the figure. E, = 18 V +1 d I2 12 0.5 2 R2 2.5 Q 12 R a 13 6.0 2 R3 1.5Q I3 0.5 Q E2 = 45 V %3D I,R2 + Eq + Iz"1 - I3R3 - Igr2 = Ez = 0 O -IR2 + Eq - I1+ I3R3 + I3r2 + E2 = 0 O -1,R2 + Eq - I1 - I;R3 - I3r2 + E2 = 0 O -I,R2 + E1 - Ir1+ I3R3 + Izr2 - E2 = 0 %3D %3D %3D
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Transcribed Image Text:Apply the loop rule to loop abcdefgha in the figure.
E, = 18 V
+1
d
I2
12
0.5 2
R2
2.5 Q
12
R
a
13
6.0 2
R3
1.5Q
I3
0.5 Q
E2 = 45 V
%3D
I,R2 + Eq + Iz"1 - I3R3 - Igr2 = Ez = 0
O -IR2 + Eq - I1+ I3R3 + I3r2 + E2 = 0
O -1,R2 + Eq - I1 - I;R3 - I3r2 + E2 = 0
O -I,R2 + E1 - Ir1+ I3R3 + Izr2 - E2 = 0
%3D
%3D
%3D
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