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Apply array: A[1] = 5, A[2] = -4, A[3] = 5, A[4] = -7, and A[5] = 7. What will be the output? FIND-MAXIMUM-SUBARRAY-LINEAR(A) max-ending-here = A[1] max-so-far = A[1] Print max-ending-here Print max-so-far for i = 2 to A.length if max-ending-here + A[i] > A[i] max-ending-here = max-ending-here + A[i] else max-ending-here = A[i] if max-so-far < max-ending-here max-so-far = max-ending-here

Apply array: A[1] = 5, A[2] = -4, A[3] = 5, A[4] = -7, and A[5] = 7. What will be the output? FIND-MAXIMUM-SUBARRAY-LINEAR(A) max-ending-here = A[1] max-so-far = A[1] Print max-ending-here Print max-so-far for i = 2 to A.length if max-ending-here + A[i] > A[i] max-ending-here = max-ending-here + A[i] else max-ending-here = A[i] if max-so-far < max-ending-here max-so-far = max-ending-here

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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4. Apply the following version of the linear-time algorithm for the maximum-subarray problem to the array: A[1] = 5, A[2] = -4, A[3] = 5, A[4] = -7, and A[5] = 7. What will be the output? FIND-MAXIMUM-SUBARRAY-LINEAR(A) max-ending-here = A[1] max-so-far = A[1] Print max-ending-here Print max-so-far for i = 2 to A.length if max-ending-here + A[i] > A[i] max-ending-here = max-ending-here + A[i] else max-ending-here = A[i] if max-so-far < max-ending-here max-so-far = max-ending-here Print max-ending-here Print max-so-far
Transcribed Image Text:4. Apply the following version of the linear-time algorithm for the maximum-subarray problem to the array: A[1] = 5, A[2] = -4, A[3] = 5, A[4] = -7, and A[5] = 7. What will be the output? FIND-MAXIMUM-SUBARRAY-LINEAR(A) max-ending-here = A[1] max-so-far = A[1] Print max-ending-here Print max-so-far for i = 2 to A.length if max-ending-here + A[i] > A[i] max-ending-here = max-ending-here + A[i] else max-ending-here = A[i] if max-so-far < max-ending-here max-so-far = max-ending-here Print max-ending-here Print max-so-far
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