AP Physics 1 Free Response Practice 1 Mechanics, Momentum 1) 1978B2(modified). A block of mass M, travels horizontally with a constant speed v, on a plateau of height H until it comes to a cliff. A toboggan of mass M, is positioned on level ground below the diff as shown above. The center of the toboggan is a distance D from the base of the cliff so that the block lands in the center of the toboggan. (a) If the block were allowed to leave the cliff at the same speed (of magnitude v,) at a small angle above the horizontal or at a small angle below the horizontal, rank the distances for the placement of the toboggan so that the block will still land in the center of the toboggan. Dis the distance from the cliff when the block leaves horizontally, De is the distance when the block leaves with a velocity above the horizontal, and Dwio, is the distance when the block leaves with a velocity below the horizontal. If any distances are the same, give them the same ranking. (1 = smallest distance from edge of cliff, 3= largest distance from edge of cliff) D Dave Explain your reasoning in words. (b) If the velocity of the block were to be increased so that it leaves the cliff horizontally with a velocity v, greater than v how does the corresponding distance D, for the block to land in the toboggan compare to the original distance D? D, < D, D, > D, D, = D, Explain your reasoning in words. (c) Determine the distance D from the base of the cliff in terms of v H, and g so that the block lands in the center of the toboggan.

AP Physics 1 Free Response Practice 1 Mechanics, Momentum 1) 1978B2(modified). A block of mass M, travels horizontally with a constant speed v, on a plateau of height H until it comes to a cliff. A toboggan of mass M, is positioned on level ground below the diff as shown above. The center of the toboggan is a distance D from the base of the cliff so that the block lands in the center of the toboggan. (a) If the block were allowed to leave the cliff at the same speed (of magnitude v,) at a small angle above the horizontal or at a small angle below the horizontal, rank the distances for the placement of the toboggan so that the block will still land in the center of the toboggan. Dis the distance from the cliff when the block leaves horizontally, De is the distance when the block leaves with a velocity above the horizontal, and Dwio, is the distance when the block leaves with a velocity below the horizontal. If any distances are the same, give them the same ranking. (1 = smallest distance from edge of cliff, 3= largest distance from edge of cliff) D Dave Explain your reasoning in words. (b) If the velocity of the block were to be increased so that it leaves the cliff horizontally with a velocity v, greater than v how does the corresponding distance D, for the block to land in the toboggan compare to the original distance D? D, < D, D, > D, D, = D, Explain your reasoning in words. (c) Determine the distance D from the base of the cliff in terms of v H, and g so that the block lands in the center of the toboggan.