ANSWERED TEST WITH ERRORS: Tess tried to solve the differential equation = 2xy – 6x. This is her work: dx dy 2ху — 6х dx dy Step 1: = (y – 3)2x dx Sdy = S 2x dx In ]y – 3| = x? + C1 eln ly-3| = ex² + C1 Step 2: %3D Step 3: Step 4: Step 5: ly – 3| = ex? + C, Step 6: y – 3 = tex² + C2 Step 7: y = ±ex² + C EXPLANATION OF CORRECTION IDENTIFIED ERROR CORRECTION OF ERROR

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Please identify the error, correct the error and explain the correction

 

ANSWERED TEST WITH ERRORS:
Tess tried to solve the differential equation
= 2xy – 6x. This is her work:
dx
dy
2ху — 6х
dx
dy
Step 1:
= (y – 3)2x
dx
Sdy = S 2x dx
In ]y – 3| = x? + C1
eln ly-3| = ex² + C1
Step 2:
%3D
Step 3:
Step 4:
Step 5:
ly – 3| = ex? + C,
Step 6:
y – 3 = tex²
+ C2
Step 7:
y = ±ex²
+ C
EXPLANATION OF
CORRECTION
IDENTIFIED ERROR
CORRECTION OF ERROR
Transcribed Image Text:ANSWERED TEST WITH ERRORS: Tess tried to solve the differential equation = 2xy – 6x. This is her work: dx dy 2ху — 6х dx dy Step 1: = (y – 3)2x dx Sdy = S 2x dx In ]y – 3| = x? + C1 eln ly-3| = ex² + C1 Step 2: %3D Step 3: Step 4: Step 5: ly – 3| = ex? + C, Step 6: y – 3 = tex² + C2 Step 7: y = ±ex² + C EXPLANATION OF CORRECTION IDENTIFIED ERROR CORRECTION OF ERROR
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