Answer True or False whether a function with growth rate is a member of the set of algorithms that grow with a certain complexity.
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Answer True or False whether a function with growth rate is a member of the set of
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- Assume that the following program segment is executed. What is the last element of testArray2 after the execution of the statement sortArray1(testArray2);? *Question 37 public static void main(String[] args) { Dog[] dogs = { new Dog(), new Dog()}; for(int i = 0; i >>"+decision()); } class Counter { private static int count; public static void inc() { count++;} public static int getCount() {return count;} } class Dog extends Counter{ public Dog(){} public void wo(){inc();} } class Cat extends Counter{ public Cat(){} public void me(){inc();} } The Correct answer: Nothing is output O 2 woofs and 5 mews O 2 woofs and 3 mews O 5 woofs and 5 mews O//Program 1 public class T1_3 { public static void main (String[] args) { int [][] arr = { {7,2,6},{6,3,2} }; for (int row = 1; row < arr.length; row++) { for (int col = 0; col < arr[0].length; col++) { if (arr[row] [col] % 2 == 1) arr[row] [col] = arr[row][col] + 1; else arr[row] [col] = arr[row][col] * 2; } What is the content of arr[][], after Program l is executed? arr[o][0]= arr[0][1]= arr[0][2]= arr[1][0]= arr[1][1]= arr[1][2]=
- public static void main(String[] args) { int[] funky = {1, -5, 3, -5, 6, 6, 6, 7, -5};int expectedFunkyRange = 5; // |6 - 1| = 5System.out.println("Expected funkyRange of " + Arrays.toString(funky) + " to be " + expectedFunkyRange + " and got " + funkyRange(funky));int[] funkyTwo = {6, 6, 4, 4, 4, 2, 2, 8, 4, 1, 1};int expectedFunkyRangeTwo = 4; // |4 - 8| = 4System.out.println("Expected funkyRange of " + Arrays.toString(funkyTwo) + " to be " + expectedFunkyRangeTwo + " and got " + funkyRange(funkyTwo)); Write a static method: public static int WeirdRange(int[] a) that that calculates the difference between the mode and "anti-mode" of an array of integers. This difference should be a positive number (you can use Math.abs to calculate an absolute value). If the array is empty or null, return -1. If the array has only one thing in it, return 0 (since the mode and anti-mode are the same). Definitions: The mode of an array is the element that occurs the most frequently.…a) FindMinIterative public int FindMin(int[] arr) { int x = arr[0]; for(int i = 1; i < arr.Length; i++) { if(arr[i]< x) x = arr[i]; } return x; } b) FindMinRecursive public int FindMin(int[] arr, int length) { if(length == 1) return arr[0]; return Math.Min(arr[length - 1], Find(arr, length - 1)); } What is the Big-O for this functions. Could you explain the recurisive more in details ?#include for(int i = 0; i { int main() for(int j = 0; j< 2; j++) { { int matrix[2][2] = { printf(" %d", matrix[i][j]); } {2,3,}, //rowo printf("\n"); } {5,7}//row1 getch(); }; } printf("\n Resultant \n"); Try to execute, screenshot the resul and try to explain the sequence of the program. Post it in space-ners provided. FRAMEWORK HTPE ADACHE e OrcE outATION roR TECHO A LE
- Code: public class RURottenTomatoes { public static void main (String[] args) { int r = Integer.parseInt(args[0]); int c = Integer.parseInt(args[1]); for ( int i = 0; i < args.length; i++ ) { int[][] array = new int[r][c]; } String input = args[0]; int n = input.length(); String temp; int arrayR = r; int arrayC = c; for ( int i = 0; i < r; i++ ) { temp = input.substring( i, i + 1 ); arrayR = arrayR + Integer.parseInt(temp); for ( i = 0; i < c; c++ ) { temp = input.substring( i + 1, i + 2 ); arrayC = arrayC + Integer.parseInt(temp); } } } } I did all this, but then stuck. I have no idea what to do next, and I think my code is wrong. Can you help me out doing this assignment? Please explain everything that you do clearly! The instructions are below: RU Rotten Tomatoes. Write program RURottenTomatoes.java that creates a 2 dimensional integer array of movie ratings from the command line arguments and displays the index of the movie that has the highest sum of ratings.…public static void main(String[] args) { int a; int b; int c; c = quad(0,1, 2); b = quad(1, 2, 3); a = quad(5, 6, 7); c = c +b+ a; } private static int quad(int a, int b, int c) { int r; r= a +b+ c; return r; } For the code above, how many entries does the activation record for method quad have? During the execution of main, at most how many activation records are existent on the run-time stack?public class Program7 { publicstaticvoidmain(String[]args){ int[]numbers=newint[100]; String[]names={"Maria","Aris","Galin","Galena"}; double[]balances=newdouble[]{2,56,12.57,36.57,57.89}; //length System.out.println(numbers.length); System.out.println(names.length); System.out.println(balances.length); //modifying names[3]="Celine Dion"; System.out.println("__________________________"); //looping for(inti=0;i<names.length;i++){ System.out.println(names[i]); } System.out.println("__________________________"); for(Stringname:names){ System.out.println(name); } //modifying array System.out.println("__________________________"); for(inti=0;i<names.length;i++){ names[i]=names[i]+" Annan"; System.out.println(names[i]); } System.out.println("__________________________"); doubletotal=0.0; for(inti=0;i<balances.length;i++){ total+=balances[i]; } System.out.println("Total Balance: "+ total); } } //calculate the average of the total balance
- public class arrayOutput { public static void main (String [] args) { final int NUM_ELEMENTS = 3; int[] userVals = new int [NUM_ELEMENTS]; int i; int sumVal; userVals [0] = 3; userVals [1] = 5; userVals [2] = 8; Type the program's output sumVal = 0; for (i = 0; i < userVals.length; ++i) { sumVal= sumVal + userVals [i]; System.out.println (sumVal); } ? ? ??public class ArrayMerge { static void arrayMerge(int a[], int b[]){ int c[] = new int[50]; int k = 0; for(int i = 0; i < a.length; i++) { c[k++] = a[i]; } for(int i = 0; i < b.length; i++) { c[k++] = b[i]; } for(int i = 0; i < k; i++) { System.out.println(c[i]); } } public static void main(String[] args) { int a[] = { 18, 36, 41, 78, 56 }; int b[] = { 10, 37, 44 }; arrayMerge(a,b); } } Calculate the algorithm step number and algorithm time complexity of the above program?int main() //default function for call { int a[100],n,i,j; for (int i = 0; i < n; i++) //Loop for ascending ordering { for (int j = 0; j < n; j++) //Loop for comparing other values { if (a[j] > a[i]) //Comparing other array elements { int tmp = a[i]; //Using temporary variable for storing last value a[i] = a[j]; //replacing value a[j] = tmp; //storing last value } } } printf("\n\nAscending : "); //Printing message for (int i = 0; i < n; i++) //Loop for printing array data after sorting { printf(" %d ", a[i]); } } Need to transform this C code to MIPS Assembly Language Code simple steps