Answer the questions below for the reaction of lithium with oxygen: 4 Li (s) + O₂(g) →2 Li₂0 (s) a) What is the charge of the lithium atoms in the reactant Li(s) b) What is the charge of the lithium ion in the product? c) Did lithium gain or lose electron(s) in this reaction? d) Was lithium oxidized or reduced? If so, how many? e) What is the charge of the oxygen atoms in the reactant O₂(g) ? f) What is the charge of the oxide ions in the product? g) Did oxygen gain or lose electron(s) in this reaction? h) Was oxygen oxidized or reduced? If so, how many?
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![### Reaction of Lithium with Oxygen
**Chemical Equation:**
\[ 4 \text{Li(s)} + \text{O}_2 \text{(g)} \rightarrow 2 \text{Li}_2\text{O (s)} \]
**Questions:**
a) What is the charge of the lithium atoms in the reactant Li(s)?
b) What is the charge of the lithium ion in the product?
c) Did lithium gain or lose electron(s) in this reaction? If so, how many?
d) Was lithium oxidized or reduced?
e) What is the charge of the oxygen atoms in the reactant O₂(g)?
f) What is the charge of the oxide ions in the product?
g) Did oxygen gain or lose electron(s) in this reaction? If so, how many?
h) Was oxygen oxidized or reduced?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F828340a0-7ac0-4702-b7a9-f2144dee3b28%2F8581235e-65d0-41ba-9f7f-1b07b45c2e1d%2F4nhjxrm_processed.png&w=3840&q=75)
A neutral atom always show "no charge".
Cation bears "+ve charge"
Anion bears "-ve charge".
A molecule or an atom is considered oxidized when it loses electrons.
A molecule or an atom is considered reduced when it gains electrons.
The charge of the monoatomic ion equals to the oxidation number.
To determine the oxidation number of an atom in the molecule, find the oxidation number of it.
Rules in calculation of oxidation number : Fluorine always bears -1 oxidation number.
Hydrogen bears +1 oxidation number with non metals and -1 oxidation number with metals.
Oxygen generally bears -2 oxidation state( -1 in peroxides).
The sum of the oxidation numbers of atoms or ions in a neutral molecule equals to zero.
The sum of the oxidation numbers of atoms or ions inn an ionic molecule equals to the charge of the molecule.
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