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Answer the questions below for the reaction of lithium with oxygen: 4 Li (s) + O₂(g) → 2 Li₂0 (s) a) What is the charge of the lithium atoms in the reactant Li(s) b) What is the charge of the lithium ion in the product? c) Did lithium gain or lose electron(s) in this reaction? d) Was lithium oxidized or reduced? XXX1. If so, how many?

Answer the questions below for the reaction of lithium with oxygen: 4 Li (s) + O₂(g) → 2 Li₂0 (s) a) What is the charge of the lithium atoms in the reactant Li(s) b) What is the charge of the lithium ion in the product? c) Did lithium gain or lose electron(s) in this reaction? d) Was lithium oxidized or reduced? XXX1. If so, how many?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Reaction Analysis: Lithium with Oxygen In this educational section, we will explore the reaction between lithium and oxygen represented by the balanced chemical equation: \[ 4 \text{Li (s)} + \text{O}_2 \text{(g)} \rightarrow 2 \text{Li}_2\text{O (s)} \] Now, let's address the questions related to this reaction: #### Questions and Answers a) **What is the charge of the lithium atoms in the reactant Li(s)?** - **Answer:** Lithium atoms in their elemental state (Li) have a charge of 0. b) **What is the charge of the lithium ion in the product?** - **Answer:** In lithium oxide (Li₂O), each lithium ion has a charge of +1. c) **Did lithium gain or lose electron(s) in this reaction? If so, how many?** - **Answer:** Lithium lost one electron, going from a charge of 0 to +1. d) **Was lithium oxidized or reduced?** - **Answer:** Lithium was oxidized because it lost electrons. e) **What is the charge of the oxygen atoms in the reactant O₂(g)?** - **Answer:** Oxygen atoms in their elemental state (O₂) have a charge of 0. f) **What is the charge of the oxide ions in the product?** - **Answer:** In lithium oxide (Li₂O), each oxide ion has a charge of -2. g) **Did oxygen gain or lose electron(s) in this reaction? If so, how many?** - **Answer:** Oxygen gained two electrons per atom, transitioning from a charge of 0 to -2. h) **Was oxygen oxidized or reduced?** - **Answer:** Oxygen was reduced because it gained electrons. This exercise illustrates the concepts of oxidation and reduction through electron transfer and how to determine the charges of atoms and ions in a chemical reaction.
Transcribed Image Text:### Reaction Analysis: Lithium with Oxygen In this educational section, we will explore the reaction between lithium and oxygen represented by the balanced chemical equation: \[ 4 \text{Li (s)} + \text{O}_2 \text{(g)} \rightarrow 2 \text{Li}_2\text{O (s)} \] Now, let's address the questions related to this reaction: #### Questions and Answers a) **What is the charge of the lithium atoms in the reactant Li(s)?** - **Answer:** Lithium atoms in their elemental state (Li) have a charge of 0. b) **What is the charge of the lithium ion in the product?** - **Answer:** In lithium oxide (Li₂O), each lithium ion has a charge of +1. c) **Did lithium gain or lose electron(s) in this reaction? If so, how many?** - **Answer:** Lithium lost one electron, going from a charge of 0 to +1. d) **Was lithium oxidized or reduced?** - **Answer:** Lithium was oxidized because it lost electrons. e) **What is the charge of the oxygen atoms in the reactant O₂(g)?** - **Answer:** Oxygen atoms in their elemental state (O₂) have a charge of 0. f) **What is the charge of the oxide ions in the product?** - **Answer:** In lithium oxide (Li₂O), each oxide ion has a charge of -2. g) **Did oxygen gain or lose electron(s) in this reaction? If so, how many?** - **Answer:** Oxygen gained two electrons per atom, transitioning from a charge of 0 to -2. h) **Was oxygen oxidized or reduced?** - **Answer:** Oxygen was reduced because it gained electrons. This exercise illustrates the concepts of oxidation and reduction through electron transfer and how to determine the charges of atoms and ions in a chemical reaction.
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