Answer the given question with a proper explanation and step-by-step solution. Decompile this code from C to MIPS ASSEMBLY CODE please thanks. upload to BB.// CpptoASM.cpp: Defines the entry point for the console application.#pragma float_control (precise)//#pragma float_control(fast)// Code that uses /fp:precise mode#include "stdafx.h"#include using namespace std;int main(){cout.precision(10);float inc= 0.000001, sum = 0.0;for (float i = 1.0; i <= 1000000.0;){sum += (1.0 / 1);i += 1.0;}cout << sum;cin.get();return 0;

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Answer the given question with a proper explanation and step-by-step solution. Decompile this code from C to MIPS ASSEMBLY CODE please thanks.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Embedded Software Development

Using specific programming languages (like C and C++) to write code for a specific hardware device in which it runs is called embedded software development. It makes the device smart by performing actions based on user's input which improves the user experience. They are designed to perform function-specific tasks rather than doing multiple tasks like computers. The embedded system is incredibly intuitive. An embedded software system could be a system developed and organized on any device, apart from an old-fashioned computer. It is the brain of a specific device; however, it is a solely useless tool and simple to elucidate what software system is embedded.

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Answer the given question with a proper explanation and step-by-step solution.

Decompile this code from C to MIPS ASSEMBLY CODE please thanks.

upload to BB.
// CpptoASM.cpp: Defines the entry point for the console application.
#pragma float_control (precise)
//#pragma float_control(fast)
// Code that uses /fp:precise mode
#include "stdafx.h"
#include <iostream>
using namespace std;
int main()
{
cout.precision(10);
float inc= 0.000001, sum = 0.0;
for (float i = 1.0; i <= 1000000.0;)
{
sum += (1.0 / 1);
i += 1.0;
}
cout << sum;
cin.get();
return 0;

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