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Answer: (fog)(x) = x² - 6x +10 Exercise: Given the functions f(x) = x² +1 and g(x) = x - 3. find (gof)(x). y your work in the box below using the Graphical equation editor. 2

Answer: (fog)(x) = x² - 6x +10 Exercise: Given the functions f(x) = x² +1 and g(x) = x - 3. find (gof)(x). y your work in the box below using the Graphical equation editor. 2

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Page 3: 3 JULUI real numbers x in the domain of g such that g(x) is in the domain off. g, denoted fo g, is defined by (fog)(x)=f(g(x)). The domain of f g is the Example: Given the functions f(x) = x² +1 and g(x) = x - 3. find (fog)(x). Solution: (fog)(x) = f(g(x)) = (x − 3)² + 1 = x² - 6x +9+1 Answer: (fog)(x) = x² - 6x +10 Exercise: Given the functions f(x) = x² + 1 and g(x) = x - 3, find (gof)(x). how your work in the box below using the Graphical equation editor.
Transcribed Image Text:Page 3: 3 JULUI real numbers x in the domain of g such that g(x) is in the domain off. g, denoted fo g, is defined by (fog)(x)=f(g(x)). The domain of f g is the Example: Given the functions f(x) = x² +1 and g(x) = x - 3. find (fog)(x). Solution: (fog)(x) = f(g(x)) = (x − 3)² + 1 = x² - 6x +9+1 Answer: (fog)(x) = x² - 6x +10 Exercise: Given the functions f(x) = x² + 1 and g(x) = x - 3, find (gof)(x). how your work in the box below using the Graphical equation editor.
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