Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![### Finding the Domain of the Rational Function
To determine the domain of the function \[ f(x) = \frac{x^2 - 36}{2x^2 + 7x - 15} \], we need to ensure that the denominator is not equal to zero, as division by zero is undefined.
#### Steps to Find the Domain:
1. **Identify the denominator**:
The denominator of the function is \( 2x^2 + 7x - 15 \).
2. **Set the denominator equal to zero**:
\( 2x^2 + 7x - 15 = 0 \).
3. **Solve the quadratic equation**:
- Use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = 2 \), \( b = 7 \), and \( c = -15 \).
- Calculate the discriminant:
\[ \Delta = b^2 - 4ac = 7^2 - 4(2)(-15) = 49 + 120 = 169 \].
- Find the roots:
\[ x = \frac{-7 \pm \sqrt{169}}{2(2)} = \frac{-7 \pm 13}{4} \].
\[ x_1 = \frac{6}{4} = \frac{3}{2} \].
\[ x_2 = \frac{-20}{4} = -5 \].
4. **Domain identification**:
The domain of the function \( f(x) \) excludes the values \( x = \frac{3}{2} \) and \( x = -5 \). Therefore,
\[ \text{Domain of } f(x) = \{ x \in \mathbb{R} \mid x \neq \frac{3}{2} \text{ and } x \neq -5 \} \].
In conclusion, the domain of the function \( f(x) = \frac{x^2 - 36}{2x^2 + 7x - 15} \) consists of all real numbers except \( x = \frac{3}{2} \) and \( x = -5 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8cf7e672-b05a-4acb-ad51-f9b37172b8f4%2F0bb557fd-8db2-4ebe-8fd3-dde7c3f3e7d0%2Ft64qs0d_processed.png&w=3840&q=75)
Transcribed Image Text:### Finding the Domain of the Rational Function
To determine the domain of the function \[ f(x) = \frac{x^2 - 36}{2x^2 + 7x - 15} \], we need to ensure that the denominator is not equal to zero, as division by zero is undefined.
#### Steps to Find the Domain:
1. **Identify the denominator**:
The denominator of the function is \( 2x^2 + 7x - 15 \).
2. **Set the denominator equal to zero**:
\( 2x^2 + 7x - 15 = 0 \).
3. **Solve the quadratic equation**:
- Use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = 2 \), \( b = 7 \), and \( c = -15 \).
- Calculate the discriminant:
\[ \Delta = b^2 - 4ac = 7^2 - 4(2)(-15) = 49 + 120 = 169 \].
- Find the roots:
\[ x = \frac{-7 \pm \sqrt{169}}{2(2)} = \frac{-7 \pm 13}{4} \].
\[ x_1 = \frac{6}{4} = \frac{3}{2} \].
\[ x_2 = \frac{-20}{4} = -5 \].
4. **Domain identification**:
The domain of the function \( f(x) \) excludes the values \( x = \frac{3}{2} \) and \( x = -5 \). Therefore,
\[ \text{Domain of } f(x) = \{ x \in \mathbb{R} \mid x \neq \frac{3}{2} \text{ and } x \neq -5 \} \].
In conclusion, the domain of the function \( f(x) = \frac{x^2 - 36}{2x^2 + 7x - 15} \) consists of all real numbers except \( x = \frac{3}{2} \) and \( x = -5 \).
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