Answer all the question below, 1. Phosphate ion (PO4) is determined by converting it to ammonium phosphomolybdate (NH4)4PO4.12M0O3 (MW=1876.5) precipitate. If 0.2711g sample produced 1.1682g of precipitate. Calculate the % of (PO4).
Answer all the question below, 1. Phosphate ion (PO4) is determined by converting it to ammonium phosphomolybdate (NH4)4PO4.12M0O3 (MW=1876.5) precipitate. If 0.2711g sample produced 1.1682g of precipitate. Calculate the % of (PO4).
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:Question 1
Answer all the question below,
1. Phosphate ion (PO4) is determined by converting it to ammonium
phosphomolybdate (NH4)4PO4.12MOO3 (MW=18765) precipitate. If 0.2711g
sample produced 1.1682g of precipitate. Calculate the % of (PO4).
2. In one gravimetric analysis to determine the % of Mn from the manganese ore,
0.6443g manganese ore was found to yield 0.4211 g Mn304. Calculate the % of
Mn in the ore.
3. In one gravimetric experiment, 0.4162 g of AgCl is obtained from a 0.9110g
sample of silver ore. Calculate the percentage of Ag in the ore.
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