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Ans: Vo = 10 mV 20 mV + 50 mV παλαι 100 mV +. – 120 mV R1 25 ΚΩ R2 20 ΚΩ Μ R3 10 ΚΩ Μ R4 50 ΚΩ Μ RF ww 50 ΚΩ 0 + 3 το 10

Ans: Vo = 10 mV 20 mV + 50 mV παλαι 100 mV +. – 120 mV R1 25 ΚΩ R2 20 ΚΩ Μ R3 10 ΚΩ Μ R4 50 ΚΩ Μ RF ww 50 ΚΩ 0 + 3 το 10

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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This image depicts a summing amplifier circuit using an operational amplifier (op-amp). The circuit consists of four voltage sources, each connected to the inverting input of the op-amp through separate resistors. ### Circuit Description: - **Voltage Sources and Resistors:** - **10 mV** through **R1** (25 kΩ) - **20 mV** through **R2** (20 kΩ) - **50 mV** through **R3** (10 kΩ) - **100 mV** through **R4** (50 kΩ) - **Feedback Resistor:** - The op-amp has a feedback resistor, **RF**, with a value of **50 kΩ**. - **Op-Amp Configuration:** - The op-amp is in an inverting configuration, meaning the input voltages are applied to the inverting terminal, and the non-inverting terminal is grounded. ### Functionality: The summing amplifier sums the input voltages after scaling them by their respective resistances, inverting the result, and then scaling it by the feedback resistance. ### Calculation: The output voltage \( V_o \) is calculated using the formula for a summing amplifier: \[ V_o = -RF \left( \frac{V_1}{R1} + \frac{V_2}{R2} + \frac{V_3}{R3} + \frac{V_4}{R4} \right) \] Substituting the given values: \[ V_o = -50kΩ \left( \frac{10 mV}{25kΩ} + \frac{20 mV}{20kΩ} + \frac{50 mV}{10kΩ} + \frac{100 mV}{50kΩ} \right) \] After calculation, the output voltage \( V_o \) is found to be **-120 mV**. **Answer: \( V_o = -120 \text{ mV} \)**
Transcribed Image Text:This image depicts a summing amplifier circuit using an operational amplifier (op-amp). The circuit consists of four voltage sources, each connected to the inverting input of the op-amp through separate resistors. ### Circuit Description: - **Voltage Sources and Resistors:** - **10 mV** through **R1** (25 kΩ) - **20 mV** through **R2** (20 kΩ) - **50 mV** through **R3** (10 kΩ) - **100 mV** through **R4** (50 kΩ) - **Feedback Resistor:** - The op-amp has a feedback resistor, **RF**, with a value of **50 kΩ**. - **Op-Amp Configuration:** - The op-amp is in an inverting configuration, meaning the input voltages are applied to the inverting terminal, and the non-inverting terminal is grounded. ### Functionality: The summing amplifier sums the input voltages after scaling them by their respective resistances, inverting the result, and then scaling it by the feedback resistance. ### Calculation: The output voltage \( V_o \) is calculated using the formula for a summing amplifier: \[ V_o = -RF \left( \frac{V_1}{R1} + \frac{V_2}{R2} + \frac{V_3}{R3} + \frac{V_4}{R4} \right) \] Substituting the given values: \[ V_o = -50kΩ \left( \frac{10 mV}{25kΩ} + \frac{20 mV}{20kΩ} + \frac{50 mV}{10kΩ} + \frac{100 mV}{50kΩ} \right) \] After calculation, the output voltage \( V_o \) is found to be **-120 mV**. **Answer: \( V_o = -120 \text{ mV} \)**
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