[ans: 9.7 m/s [N 52° W] 2. A star of mass 2 x 1030 kg moving with a velocity of 2 × 104 m/s [E] collides with a second star of mass 5 x 1030 kg moving with a velocity of 3 x 104 m/s at a right angle to the path of the first star. If the two join together, what is their common velocity? A [ans: 2 x 104 m/s [15° to the initial path of the second star]]

[ans: 9.7 m/s [N 52° W] 2. A star of mass 2 x 1030 kg moving with a velocity of 2 × 104 m/s [E] collides with a second star of mass 5 x 1030 kg moving with a velocity of 3 x 104 m/s at a right angle to the path of the first star. If the two join together, what is their common velocity? A [ans: 2 x 104 m/s [15° to the initial path of the second star]]

Name: SHARPADVANCED D.A.HOME2nd FRANDOM re7n!nCr4ExyMDF[ans: 9.7 m/s [N 52°
Uploaded: 2024-03-20T06:57:37.000Z
Channel: Bartleby
Description: SHARPADVANCED D.A.HOME2nd FRANDOM re7n!nCr4ExyMDF[ans: 9.7 m/s [N 52° W]2. A star of mass 2 × 1030 kg moving with a velocity of 2 × 104 m/s [E] collides with a secondstar of mass 5 × 1080 kg moving with a velocity of 3 x 104 m/s at a right angle to

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: Two cars collide. One car of mass 1.13 x103kg is initially travelling at 25.7 m/s [E]. The other car…

Q: A professional golfer is examining a video of a practice swing. The high‑speed footage shows that…

A: the magnitude of the impulse imparted to the ball by the club is I=Δp=mvf-vi=0.0459 kg176…

Q: Suppose the particles shown below have masses m, = 0.18 kg, m, = 0.36 kg, m, = 0.54 kg, m, = 0.72…

Q: An object is traveling in the negitve x-direction at 23.4 kg m/s of momentum and 7.71 J of kinetic…

A: momentum = mv = 23.4 kg m/s kinetic energy = 7.71 J

Q: nter the x , y , and z components of the velocity

Q: Extra: An electron (mass = 9.1 × 10-31 kg) is accelerated from rest to a speed of 2 x 10% m/s in 1…

Q: Bryce, a mouse lover, keeps his four pet mice in a roomy cage, where they spend much of their spare…

A: Given: Mass of the first mice = 0.0167 Kg Mass of the second mice = 0.0231 Kg Mass of the third mice…

Q: Is this situation possible? If not, why not? A stationary particle fragments into two particles. One…

A: This situation is not possible.

Q: A 1.672*10^-27 kg proton is traveling at (5.0x10^6) m/s. How many N.s of momentum does it have?

A: Given data: Mass of proton (m) = 1.672×10-27 kg Velocity (v) = 5.0×106 m/s

Q: Bryce, a mouse lover, keeps his four pet mice in a roomy cage, where they spend much of their spare…

A: Given , masses m1 =0.0103 kgm2 = 0.0133 kgm3 = 0.0195 kgm4 = 0.0185 kg velocities v1x =0.585 m/sv1y…

Q: Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are…

Q: Two particles and B have the same momenta. Particle A is 3.0 times as massive as particle B (i.e. M.…

A: Answer 0.3

Q: Block 1 with a mass of 1.0 kg slides down a frictionless ramp with a height of 3.0 m and collides…

A: Mass of block 1 (M1) = 1.0 kg Height (H) = 3.0 m Mass of block 2 (M2) = 2.0 kg Friction coefficient…

Q: 1. a) For a particle of mass m and velocity v, what are the momentum, and its (kinetic) energy?…

Q: A proton is traveling to the right at 2.0 x 107 m/s. It has a head-on perfectly elastic collision…

Q: A block of mass m= 2 kg is moving with speed 7ms^-1. It collides inelastically with a stationary…

A: Mass, m = 2 kgSpeed, u = 7 m/sMass, M = ? Speed, v = 0Combined speed, V = 5 m/s

Q: 2. A 40 kg astronaut is floating in space, initially motionless in the reference frame of her nearby…

A: Given an astronaut in space with mass ma=40kg let the mass of the oxygen canister mo=5kg Initially…

Q: Space probes may be separated from their launchers by exploding bolts. (They bolt away from one…

A: Kinetic Energy=7000J m1= mass of satellite m2=mass of launcher v1=velocity of satellite after…

Q: Bryce, a mouse lover, keeps his four pet mice in a roomy cage, where they spend much of their spare…

Q: A Neptunium-237 nucleus, initially at rest, decays by emitting an alpha particle. The resulting…

A: Mass of Neptonium, MNp = 237 u Mass of protactinium, Mpa = 233 u Mass of alpha particle, Malpha = 4…

Q: An 8.24 kg mass moving east at 17.2 m/s on a frictionless horizontal surface collides with a 11.4 kg…

Q: $F$ thetaS A block initially at rest is pulled by a force of magnitude F at an angle 0. If 0 =…

A: CONCEPT:

Q: A 3kg mass with an initial velocity of (6)m/s collides with and sticks to a Skg mass with an initial…

A: Given that mass, m1 = 3 kg The initial velocity of m1, u1 = (6i) m/s The mass, m2 = 5 kg

Q: 2.2.1) If in the above collision the masses of the particles are m1 = m and m2= 4m and u1/u2 = 3.…

A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…

Q: The equation a = Fnet / m is valid in any dimension. That is, a = Fnet / m implies ax = Fnet x / m…

Topic Video

Question

SHARP
ADVANCED D.A.
HOME
2nd F
RANDOM re
7
n!
nCr
4
Exy
MDF
[ans: 9.7 m/s [N 52° W]
2. A star of mass 2 × 1030 kg moving with a velocity of 2 × 104 m/s [E] collides with a second
star of mass 5 × 1080 kg moving with a velocity of 3 x 104 m/s at a right angle to the path
of the first star. If the two join together, what is their common velocity? TA [ans: 2 x 10“ m/s
[15° to the initial path of the second star]]
252
Chapter 5 • Momentum and Collisions

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

C Chegg X C Sign In https://bconline.broward.edu/d21/lms/quizzing/user/attempt/quiz_start_frame_auto.d2l?ou=514283&is... A Q If a projectile mass of 1.0 kg moving at 19.0 m/s collides with a motionless target mass of 15.0 kg perfectly inelastically what is the total kinetic energy of the projectile and target after the collision? X 1 OneLoc X Quizzes X Q instagra X Your Answer: Use standard MKS unit abbreviations. Instagra X Answer units (75,834 X C Reset P. X X New ta X + {}
2. A 62 kg student stands on a 36 kg cart that is free to move in any direction. The cart and student are moving together with a velocity of 2.7 m/s [S]. The student then starts to walk so that her velocity is 3.1m/s [ E25oN] relative to the floor. Calculate the new velocity of the cart.
We know that the mass of the bagged lunch is m = 1.40 kg and the mass of the astronaut is M = 67.0 kg. Before the collision, the bagged lunch moves with a velocity of vi = 1.60 m/s in the positive x-direction and the astronaut is at rest relative to the space station with velocity Vi = 0. MVi + mvi = MVf + mvf to obtain (67.0 kg)(0 m/s) + (1.40 kg)(1.60 m/s) = (67.0 kg)Vf + (1.40 kg)vf. Because vf = Vf, this further simplifies to (67.0 kg)(0 m/s) + (1.40 kg)(1.60 m/s) = (1.40 kg + 67.0 kg)Vf. What is the velocity of the astronaut after the collision?
3. Consider the following two types of completely inelastic collisions between Турe A two identical masses, m. Type A: a m m particle of mass m and velocity v strikes V a stationary target consisting of an identical particle of mass m. Type B: Туре В each particle has a mass m and a speed m m v/(22) – in this case they collide head v/2/2 V/22 on. Ignore gravity, and express your answers in terms of m and v. A. What is the speed of the center of mass for type A, and for type B collisions (before the collision occurs)? What the center of mass speed after the collision for each type of collision. Justify your answers. В. ( What is the change in the total kinetic energy for type A and type B ?
A 212^Bi (bismuth) nucleus undergoes alpha decay, resulting in a 208^Tl (thallium) nucleus and a 4He (helium) nucleus as per the following reaction: 212^Bi →208^Tl + 4^He The masses of each nucleus is listed in the table below. Given that the bismuth atom was at rest before the reaction, if the resulting thallium nucleus is traveling 3.3 × 105 m/s, how fast is the helium nucleus traveling?
There are two particles (1 and 2) that are moving around in space. The mass of particle 1 is 4.1 kg and the mass ofparticle 2 is 4.51 kg. The particles are isolated so that only the forces between the particles are significant. The forcethat 2 exerts on 1 is given by: F21(t) = Fxe−(t/tx )ˆi + Fy sin(2πt/T)ˆj The initial time is t = 0 s and the final time is t = 5.9 s The y-component of the impulse from 1 on 2 is: I12,y = 50.28 N s Fx = 17.4 N, Fy = -28.8 N, tx = 6.5 s, T = 60.7 s what is the x component of the impulse from 1 on 2? What is the y-component of the change in momentum for particle 1? what is the y componentof the average force from 1 on 2
Multiple-Concept Example 6 reveiws the principles that play a role in this problem. A nuclear power reactor generates 3.8 × 10° W of power. In one year (365.25 days), what is the change in the mass of the nuclear fuel due to the energy being taken from the reactor? Number i Units
2. A projectile of mass m = target of mass M = 2 kg and gets imbedded in it. The energy lost (AE) during this 0.2kg and initial speed v; = 200 ms-1 hits a stationary collision is closest to (a) AE = 0J (no energy is lost) (b) AE = -3640 J (c) AE = -3670 J (d) ДЕ - = -4000 J
Two particles A and B are moving towards each other along the x-direction with speeds VA = 2 m/s and vB = 2 m/s, as shown in the figure below. The masses are respectively mA =1 kg and mB = 1.2 kg. The coefficient of restitution e = 0.5. A V₁ VAX = -2.36 m/s VAX=- 1.27 m/s VAX=-0.18 m/s VAX = 2 m/s VB B X Calculate the x-component of the velocity vector of particle A after impact (magnitude and sign); give your answer in the coordinate system shown in m/s.
In the four momentum treatment of relativistic particle collisions or decays, The mass of a particle is different for various observers. O Momentum and energy are still conserved in any inertial frame of reference. O The energy equals the sum of the momentum, pc, plus the mass, mc2. O The momentum and energy for a process are the same in all frames of reference.
Question 2
A child on ice skates with a mass of 35 kg and a velocity of 7.5 m/s [S] undergoes a collision with a second child on ice skates with a of mass 45 kg and a velocity of 3.5 m/s [S30°E]. If the two children become entangled during the collision, determine their final velocity.