and they are independent

MATLAB: An Introduction with Applications
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**Bivariate Time Series Model Analysis**

*Consider the following bivariate time series model:*

\[ x_t = w_t, \quad y_t = w_t + w_{t-1} + u_t, \]

*where \(\{w_t\}\) and \(\{u_t\}\) are standard (variance = 1) Gaussian white noise, and they are independent of each other.*

**Objective:**
Show that \((x_t, y_t)\) are jointly weakly stationary.

**Explanation:**

- \(x_t\) is equal to \(w_t\), which is a standard Gaussian white noise process with a mean of 0 and variance of 1.
  
- \(y_t\) is composed of three components: \(w_t\), the previous term \(w_{t-1}\), and another noise component \(u_t\). Each has a mean of 0 and variance of 1, and they contribute to the overall behavior of \(y_t\).

**To Show Joint Weak Stationarity:**

1. **Mean Constancy:**
   - Verify that both \(x_t\) and \(y_t\) have constant means over time.
   - Since each component is Gaussian white noise with a mean of 0, both \(x_t\) and \(y_t\) also have a mean of 0.

2. **Constant Variance:**
   - The variance for \(x_t\) is simply the variance of \(w_t\), which is 1.
   - The variance for \(y_t\) includes contributions from \(w_t\), \(w_{t-1}\), and \(u_t\), calculated as:
     \[
     \text{Var}(y_t) = \text{Var}(w_t) + \text{Var}(w_{t-1}) + \text{Var}(u_t) = 1 + 1 + 1 = 3
     \]

3. **Covariance Consistency:**
   - Calculate the covariance between \(x_t\) and \(y_t\).
   - Since \(x_t\) only depends on \(w_t\), the covariance comes from the shared \(w_t\) component, resulting in:
     \[
     \text{Cov}(x_t, y_t) = \text{Cov}(w_t, w_t) = 1
     \
Transcribed Image Text:**Bivariate Time Series Model Analysis** *Consider the following bivariate time series model:* \[ x_t = w_t, \quad y_t = w_t + w_{t-1} + u_t, \] *where \(\{w_t\}\) and \(\{u_t\}\) are standard (variance = 1) Gaussian white noise, and they are independent of each other.* **Objective:** Show that \((x_t, y_t)\) are jointly weakly stationary. **Explanation:** - \(x_t\) is equal to \(w_t\), which is a standard Gaussian white noise process with a mean of 0 and variance of 1. - \(y_t\) is composed of three components: \(w_t\), the previous term \(w_{t-1}\), and another noise component \(u_t\). Each has a mean of 0 and variance of 1, and they contribute to the overall behavior of \(y_t\). **To Show Joint Weak Stationarity:** 1. **Mean Constancy:** - Verify that both \(x_t\) and \(y_t\) have constant means over time. - Since each component is Gaussian white noise with a mean of 0, both \(x_t\) and \(y_t\) also have a mean of 0. 2. **Constant Variance:** - The variance for \(x_t\) is simply the variance of \(w_t\), which is 1. - The variance for \(y_t\) includes contributions from \(w_t\), \(w_{t-1}\), and \(u_t\), calculated as: \[ \text{Var}(y_t) = \text{Var}(w_t) + \text{Var}(w_{t-1}) + \text{Var}(u_t) = 1 + 1 + 1 = 3 \] 3. **Covariance Consistency:** - Calculate the covariance between \(x_t\) and \(y_t\). - Since \(x_t\) only depends on \(w_t\), the covariance comes from the shared \(w_t\) component, resulting in: \[ \text{Cov}(x_t, y_t) = \text{Cov}(w_t, w_t) = 1 \
Suppose \(\{y_t\}\) is given as in Problem 1, while \(\{x_t\}\) is instead given by the following signal-plus-noise model:

\[ x_t = t + y_t. \]

Find the **bivariate autocorrelation function** \(\rho_x(s, t)\) of \(\{x_t\}\) with justification. Hint: identify first which is the signal term (non-random) and which is the noise term (random, mean zero).
Transcribed Image Text:Suppose \(\{y_t\}\) is given as in Problem 1, while \(\{x_t\}\) is instead given by the following signal-plus-noise model: \[ x_t = t + y_t. \] Find the **bivariate autocorrelation function** \(\rho_x(s, t)\) of \(\{x_t\}\) with justification. Hint: identify first which is the signal term (non-random) and which is the noise term (random, mean zero).
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