and observe the two structures determined below for interleukin 13. Write a short essay to discuss which type of 2D-NMR can yield this type of result and describe the difference between the two structures while specifically invoking the number of restraints and the resolution (in angstroms). interleukin 1B 2780 distance restraints 536 distance restraints RMSD (backbone atoms) = 2.0 angstroms RMSD (backbone atoms) = 0.4 angstroms 14019

and observe the two structures determined below for interleukin 13. Write a short essay to discuss which type of 2D-NMR can yield this type of result and describe the difference between the two structures while specifically invoking the number of restraints and the resolution (in angstroms). interleukin 1B 2780 distance restraints 536 distance restraints RMSD (backbone atoms) = 2.0 angstroms RMSD (backbone atoms) = 0.4 angstroms 14019

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Make a table with a scale of absorbance and the concentration of protein in Chromatin sample from the following data for excel graph Absorbance=660nm following data are of tubes with concern A =0 B=0.036 C=0.011 D=0.001 E=0.027 F=0.020 G=0.032 H1=0.176 H2=0.183 I1=0.150 I2=0.171 also plot the graph??
Consider the following properties of the protein components of a sample mixture as provided in the table below: 1. if the mixture is subjected to gel filtration chromotography which protein component elute first? 2. if the mixture is subjected to isoelectric focusing which protein will stop m oving nearest to the positive electrode? 3. if the mixture is subjected to cation-exchange chromotography using a buffer at ph 7 which protein will bind to the resin? 4.if the mixture is subjected to SDS-PAGE which protein will be at bottomost portion of gel? 5.if the mixture is subjected to hydrophobic interaction chromotography which protein will bind most strongly to the resin?
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Do letter 4 and draw a titration curve as directed in letter 4 c) for pka 4.7, labelling all the axes.
The A280 of a protein sample loaded onto a gel was determined to be 0.767 (1.00 cm path length, after subtracting the blank). The total volume of this sample was 428 µL. 19.0 µL of this protein sample was mixed with 19.0 µL of 2X laemalli sample buffer and then 12.0 µL of the entire sample was loaded into the gel and electrophoresed. Calculate the amount of protein that was loaded into the gel (in µg).
Protein concentration can readily be determined using the Beer-Lambert law: A = e l c where A = absorbance e = molar absorption coefficient (M-1cm-1) l = light path length (cm) c = concentration (M) If the molar absorption coefficient at 280 nm for yeast ADH is 48860 M-1cm-1 and a 10 mL solution of the protein has an absorbance at 280 nm of 0.4 (as measured by a spectrometer with pathlength 1 cm), then what is the concentration of the protein solution (in μM)? i.e. concentration = ______ μM If the molecular weight of the protein is 36849, what is its concentration in mg/mL? i.e. concentration = _______ mg/mL For each part of the question, show your calculations to arrive at your answers.
Suppose that you are tasked to determine the protein concentration of an unknown protein solution via Bradford assay. You prepared six solutions of bovine serum albumin (BSA) with different concentrations. The initial concentration of the BSA stock solution is 7.50 mg/mL. Approximately 200 µL of Bradford Reagent was added to each of these solutions and the absorbance at 595 nm was taken after 5 minutes. See the table below for data on the standard solutions. Standard # A595 BSA conc (mg/mL) 0.000 0.158 2 1.125 0.291 2.250 0.372 4 3.375 0.503 5 4.500 6 5.625 0.675 Determine the protein concentration, in mg/mL, of the unknown solution if its absorbance at 595 nm was 0.248. Note: Final answer format must be x.xx (two decimal places). Round off only in the final answer. Do not round off in the middle of calculation.
Please give me correct solution for both questions c and d.
The purification continues with a cation exchange step in which the positively charged cytochrome C protein is separated from negatively charged DNA and other proteins. The cation exchange eluate (volume of solution collected) had a total volume of 42.0 mL and a 1.0 mL aliquot was set aside for further analysis. The following data was obtained from the 1.0 mL aliquot to quantify the protein amount and purity: The absorbance at 410 nm of the aliquot was diluted 5-fold was 0.474 (1 cm pathlength). The absorbance at 595 nm from a 1.0 mL Bradford Assay solution that was diluted by 100-fold from the aliquot was 0.195 (1 cm pathlength). Using the information given, Calculate the total protein amount in mg from the absorbance at 595 nm. Calculate the cytochrome C amount in mg from the absorbance at 410 nm using Beer’s Law.
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The amino acid tyrosine has an extinction coefficient of 1405 M-1cm-1 at 274nm. Calculate: The A274 of a 0.4mM solution of tyrosine measured in a cuvette with a 1 cm light path. The concentration of a solution of tyrosine with A274865 after 12-fold dilution measured in a cuvette with a 1 cm light path.