Independent random samples were selected from two normal populations with means 4, and u,and equal variances. The mean of population 1 (4 ) is different from the mean of population 2(4,) is tested. The 95% confidence interval for (µ, -µ.) is (1.5, 4.5). Then the p(x > 4.5) equals:

Given information: 95% confidence interval for μ1-μ2 is 1.5, 4.5.

and H2 Independent random samples were selected from two normal populations with means and equal variances. The mean of population 1 (µ ) is different from the mean of population 2 (4,) is tested. The 95% confidence interval for (H, - 4) is (1.5, 4.5). Then the p(x > 4.5) equals:

and H2 Independent random samples were selected from two normal populations with means and equal variances. The mean of population 1 (µ ) is different from the mean of population 2 (4,) is tested. The 95% confidence interval for (H, - 4) is (1.5, 4.5). Then the p(x > 4.5) equals:

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

What critical value of t* should be used for a 95% confidence interval for the population mean based on a random sample of 21 observations? Find the t-table here. t* = 1.721 t* = 1.725 t* = 2.080 t* = 2.086
I have tried multiple ways to solve this but I am just not getting it! Any assisstance I will greatly appreciate.
In the past, a chemical company produced 880 pounds of a certain type of plastic per day. Now, using a newly developed and less expensive process, the mean daily yield of plastic for the first 50 days of production is 871 pounds; the standard deviation is 21 pounds. Do the data provide sufficient evidence to indicate that the mean daily yield for the new process is less than that of the old procedure? (Use α=0.05) (c) p-value for the test above is
The admissions office at Memorial Hospital recently stated that the mean age of its patients was μ= 43 years with σ = 21.2 years. A random sample of 29 ages obtained from the admissions office records had a mean of 49.9 years. A hospital administrator doesn’t believe that a mean of 43 years is correct. Calculate the critical value AND answer does the evidence support the hospital’s claim (H_o) or the administrator’s claim (H_a) at the α = 0.05 level?
A sample of 66 night-school students' ages is obtained in order to estimate the mean age of night-school students. x = 24.7 years. The population variance is 18. (a) Give a point estimate for u. (Give your answer correct to one decimal place.) (b) Find the 95% confidence interval for u. (Give your answer correct to two decimal places.) Lower Limit Upper Limit (c) Find the 99% confidence interval for u. (Give your answer correct to two decimal places.) Lower Limit Upper Limit
The additional growth of plants in one week are recorded for 11 plants with a sample standard deviation of 2 inches and sample mean of 12 inches. t* at the 0.05 significance level = Ex: 1.234 Margin of error = Ex: 1.234 Confidence interval = [ Ex: 12.345 E, Ex: 12.345 ]
An SRS of 400 high school seniors gained an average of x = 21.87 points in their second attempt at the SAT Mathematics exam. Assume that the change in score has a Normal distribution with standard deviation o = 48.66. We want to estimate the mean change in score µ in the population of all high school seniors. (a) Using the 68-95-99.7 Rule or the z-table (Table A), give a 95% confidence interval (a, b) for u based on this sample. (Enter your answers rounded to three decimal places. If you are using CrunchIt, adjust the default precision under Preferences as necessary. See the instructional video on how to adjust precision settings.) a: b: (b) Based on your confidence interval in part (a), how certain are you that the mean change in score u in the population of all high school seniors is greater than 0? O The upper endpoint of the interval is larger than 0, so we are 95% certain that the mean change in score in the population of all high school seniors is greater than 0. O We cannot be…
A sample of n=52 heights (in cm). of women yielded a mean of x=163.769 and a standard deviation of s=6.4319, variance v=41.3693 for the hypotheses H0:μ=163.769 H0:μ<163.769 CALCULATE THE P-VALUE (Perform a normality test on the data, Proposal of hypotheses of independent means,Perform a test for equality of variances)
The mean and the standard deviation of the sample of 100 bank customer waiting times are x¯ = 5.36 and s = 2.455. (1) Calculate a t-based 95 percent confidence interval for µ, the mean of all possible bank customer waiting times using the new system. (2) Are we 95 percent confident that µ is less than 6 minutes?.
A random sample of size 100 is taken from a normal distribution population with sigmma=4.3. give that the sample mean is x bar =19.8 construct a 95%confidence interval for the position mean mu.( Round to two decimals)
Let X1,., X, be iid from Normal(e,0) population (0>0). Use the pivotal quantity to find (1-a) Confidence Interval for 0. ...
Vehicle speeds at a certain highway location are believed to have approximately a normal distribution with mean µ = 50 mph and standard deviation σ = 5 mph. The speeds for a randomly selected sample of n = 25 vehicles will be recorded. (a) Give numerical values for the mean and standard deviation of the sampling distribution of possible sample means for randomly selected samples of n = 25 from the population of vehicle speeds. Mean = s.d.(x) = (b) Use the Empirical Rule to find values that fill in the blanks in the following sentence. For a random sample of n = 25 vehicles, there is about a 95% chance that the mean vehicle speed in the sample will be between and mph. (c) Sample speeds for a random sample of 25 vehicles are measured at this location, and the sample mean is 59 mph. Given the answer to part (b), explain whether this result is consistent with the belief that the mean speed at this location is μ = 50 mph. A sample mean of 59 mph (when n = 25) --Select--- be consistent with…