Example 11.8. In a 50 kVA, 11 kV/400 V transformer, the iron and copper losses are 500W and 600 W respectively under rated conditons.(i) Calculate the efficiency on unity power factor at full load.

Given : Rating of transformer= 50 KVA Pi=500WPc=600 Wcosϕ=1

Answered: and 600 W respectively under rated…

Engineering

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and 600 W respectively under rated conditons. (i) Calaulate the offician an an organ fanton at full load

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

Example 11.8. In a 50 kVA, 11 kV/400 V transformer, the iron and copper losses are 500
W and 600 W respectively under rated conditons.
(i) Calculate the efficiency on unity power factor at full load.

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