Example 11.8. In a 50 kVA, 11 kV/400 V transformer, the iron and copper losses are 500W and 600 W respectively under rated conditons.(i) Calculate the efficiency on unity power factor at full load.

Given : Rating of transformer= 50 KVA Pi=500WPc=600 Wcosϕ=1

Answered: and 600 W respectively under rated…

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and 600 W respectively under rated conditons. (i) Calaulate the offician an an organ fanton at full load

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.4MCQ: An ideal transformer has no real or reactive power loss. (a) True (b) False

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

Example 11.8. In a 50 kVA, 11 kV/400 V transformer, the iron and copper losses are 500
W and 600 W respectively under rated conditons.
(i) Calculate the efficiency on unity power factor at full load.

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