& 6.2Question 15, 6.1.38-TPart 1 of 4>HW Score: 48.86%, 17.1 of 35 pointsO Points: 0 of 1SaveYou are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean.Interpret the results and compare the widths of the confidence intervals.From a random sample of 36 months from January 2006 through December 2020, the mean number of tornadoes per month in the United States was about 104. Assumethe population standard deviation is 118.The 90% confidence interval is(Round to two decimal places as needed.)thisView an exampleGet more help -叮F3SearchF12F7F8F9F10F4F5F6*Clear allDelete+BackspaceNumLock10:05 PM3/17/2024*+

The objective of this question is to construct the 90% and 95% confidence intervals for the…

Answered: & 6.2 Question 15, 6.1.38-T Part 1 of 4…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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please help with these questions, thank you Q5:A manufacturer wishes to estimate, within 13 hours, the true mean lifetime of light bulbs. If she wishes to be 97% confident, how many light bulbs should be sampled? The population standard deviation is known to be 85 hours.
A random sample of 82 women showed that the mean number of children reported was 1.87 with a standard deviation of 1.7 . (Interestingly, a sample of 82 men showed a mean of 1.3 children.) Complete parts (a) through (c) below. LOADING... Click the icon to view the t-table. Question content area bottom Part 1 a. Find a 95% confidence interval for the population mean number of children for women. Because the sample size is so large, you can use 1.96 for the critical value of t (which is the same as the critical value of z) if you do the calculations manually. Choose the correct answer below and, if necessary, fill in the answer boxes to complete your choice. (Type integers or decimals rounded to the nearest hundredth as needed. Use ascending order.)
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Suppose the mean height in inches of all 9th grade students at one high school is estimated. The population standard deviation is 5 inches. The heights of 9 randomly selected students are 73, 66, 64, 67, 70, 63, 64, 72 and 72. = _______ Margin of error at 90% confidence level = ________ 90% confidence interval = _______, _________
Part d) where does the 0.675 come from?
In a study on running and happiness, runners indicated the number of miles they ran in a day and their subsequent score on a Happiness Survey (higher score = greater happiness). Runner # of miles (x) Happiness Score (y) 1 16 12 2 4 3 12 14 4 2 8 For these data: The mean of miles run is: 8.50 The mean of the Happiness scores is: 10.00 The standard deviation of the Miles scores is: 5.72 The standard deviation of the Happiness scores is: 3.16 In your submission, please include a copy of the SPSS or Excel output and answer the following: A. What is the r and r? value? B. Based on Pearson's r and r2 value, describe the relationship (direction/strength) that exists between # of miles run and Happiness scores. C. Create a scatterplot for the data using Excel or SPSS (include output in your submission). D. Insert the prediction line from Excel/SPSS on your scatterplot.
DATAfile: Costco You may need to use the appropriate technology to answer this question. Consumer Reports uses a 100-point customer satisfaction score to rate the nation's major chain stores. Assume that from past experience with the satisfaction rating score, a population standard deviation of ? = 13 is expected. In 2012, Costco, with its 432 warehouses in 40 states, was the only chain store to earn an outstanding rating for overall quality. A sample of 15 Costco customer satisfaction scores follows. 95 90 83 75 95 98 80 83 82 93 86 80 94 64 62 (a) What is the sample mean customer satisfaction score for Costco? (b) What is the sample variance? (Round your answer to two decimal places.) (c) What is the sample standard deviation? (Round your answer to two decimal places.) (d) Construct a hypothesis test to determine whether the population standard deviation of ? = 13 should be rejected for Costco. With a 0.05 level of significance, what is your conclusion?…
You are interested in finding a 98% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute miles for 11 randomly selected non-residential college students. Round answers to 3 decimal places where possible. 18 18 27 17 15 7 11 15 9 12 19 a. With 98% confidence the population mean commute for non-residential college students is between _____ and____miles. b. If many groups of 11 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About (____) percent of these confidence intervals will contain the true population mean number of commute miles and about(_____) percent will not contain the true population mean number of commute miles.
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A test of writing ability is given to a random sample of 11 students before and after they completed a formal writing course. The results are given below: Before: Mean = 80.27, standard deviation = 12.76 After: Mean = 78.27, standard deviation = 12.92 Before/After: Mean = 2, standard deviation = 2.65 Construct a 99% confidence interval for the mean differencebetween the before and after scores. Round your answer to 3 decimal places.
Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week. A sample of 65 weekly reports showed a sample mean of 19.5 customer contacts per week. The sample standard deviation was 4.2. Provide a 90% confidence interval for the population mean number of weekly customer contacts for the sales personnel. (Round your answers to two decimal places.) _________ contacts/week to ___________contacts/week Provide 95% confidence interval for the population mean number of weekly customer contacts for the sales personnel. (Round your answers to two decimal places.) ___________contacts/week to ___________contacts/week
Question A hospital would like to determine the mean length of stay for its patients having abdominal surgery. A sample of 17 patients revealed a sample mean of 5.7 days and a sample standard deviation of 1.6 days. Assume that the lengths of stay are approximately normally distributed. Find a 95% confidence interval for the mean length of stay for patients with abdominal surgery. Round the endpoints to two decimal places, if necessary. Lower Endpoint= Upper Endpoint=

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