Answered: Analysis shows that a 2.750 mL sample…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Analysis shows that a 2.750 mL sample of a diprotic acid reacts completely with330.0 mL of 0.2000 M KOH solution. What is the molar mass of the unknown acid? (density of unknown diprotic acid = 1.200 g/mL)

Expert Solution

Step 1

Given that:

Volume of diprotic acid = 2.750 mL
Density of diprotic acid = 1.200 g/mL
Diprotic acid reacts completely with 330.0 mL of 0.2000 M KOH solution.

To determine: Molar mass of the unknown acid.

Step 2

Number of moles of KOH in 330.0 mL of 0.2000 M solution is,

$\begin{array}{l} Moles of KOH = (Concentration) (Volume in mL \times 10^{- 3}) \\ Moles of KOH = (0.2000) (330.0 \times 10^{- 3}) \\ Moles of KOH = 0.066 mol \end{array}$

Step 3

Calculate moles of diprotic acid

A diprotic acid is an acid that can give two H⁺ ions. That is why, to neutralize one mole of diprotic acid there is required two moles of KOH (i.e. monoprotic base).

Thus, 2 mol of KOH reacts completely with 1 mol of diprotic acid.
Therefore, 0.066 mol of KOH reacts completely with $\frac{1}{2} \times 0.066$ = 0.033 mol of diprotic acid.

Moles of diprotic acid = 0.033 mol

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