Analysis of time series data for a given site has yielded an average velocity of 6 m/s. It is determined that a Rayleigh wind speed distribution gives a good fit to the wind data. a) Based on a Rayleigh wind speed distribution, estimate the number of hours that the wind speed will be between 9.5 and 10.5 m/s during the year. b) Using a Rayleigh wind speed distribution, estimate the number of hours per year that the wind speed is equal to or above 16 m/s.
Analysis of time series data for a given site has yielded an average velocity of 6 m/s. It is determined that a Rayleigh wind speed distribution gives a good fit to the wind data. a) Based on a Rayleigh wind speed distribution, estimate the number of hours that the wind speed will be between 9.5 and 10.5 m/s during the year. b) Using a Rayleigh wind speed distribution, estimate the number of hours per year that the wind speed is equal to or above 16 m/s.
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
Transcribed Image Text:Analysis of time series data for a given site has yielded an average velocity of 6 m/s. It
is determined that a Rayleigh wind speed distribution gives a good fit to the wind data.
a) Based on a Rayleigh wind speed distribution, estimate the number of hours that
the wind speed will be between 9.5 and 10.5 m/s during the year.
b) Using a Rayleigh wind speed distribution, estimate the number of hours per year
that the wind speed is equal to or above 16 m/s.
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