An x-ray photon escapes the accretion disk of a black hole of 5 solar masses and a radius of 14.7 km. Calculate the redshift caused by the gravity of the black hole.
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Q: The radius at which nothing can escape the pull of a black hole is called the ________.
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A: As per general relativity when a photon leaves a gravitational well its wavelength will increase…
- As per general relativity due to space-time curvature, the frequency of the photon will reduce as it moves away from a gravitational source. When a photon leaves a gravitational well redshift takes place and is called gravitational redshift.
- The gravitational redshift caused by a strong source is given by,
Here z is the gravitational redshift, G is Newton’s gravitational constant, M is the mass of the object, r is the photon’s starting distance from M, and c is the speed of light.
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- A gamma ray burst delivers approximately 5.0 X10-6 joules/m2 to a detector on an orbiting space telescope. Assuming that the red shift indicates that the source is 5 X109 light years away (1 yr =3.16X107 seconds) and that the energy at the detector has been corrected for the redshift, what is the energy output of the source in units of 1047 joules and how does it compare to the rest energy of the Sun. The speed of light is 3.0 X 108 m/sec. A year is 3.16 X 107 sec. The mass of the Sun is 2 X 1030 kg. Rest mass energy is E=mc2. The surface area of a sphere is 4πr2.You discover by dropping particles into it that the Event Horizon (Schwartzschild Radius) of a black hole is 171 km. How massive is it? (enter just the number in solar masses)The typical core-collapse supernova has an energy budget of about 1046 J. This energy comes from the gravitational potential energy of an inner core with mass Mic, which collapses from an initial radius of 5 x 106 m down to the final radius of 50 km. Estimate Mic, in solar masses, for this to be a realistic energy source of the core-collapse supernova. You may assume that the density before the collapse is uniform. Discuss briefly how a Type la supernova is different from a core-collapse supernova from a massive star?
- Event Horizon is a region around a black hole where: group of answer choices: even light cannot escape. all the events are occurring speed of an object is close to speed of light. no physical object can pass through. r nothing can enter .Assume a neutron star has a mass of about 1.2 times the mass of the Sun and a radius of 7 kilometers. If the escape speed is V2esc=2GM/R, work out the formula for the radius of the Event Horizon around a Black Hole of mass M.Calculate the Schwarzschild radius of the Sun.
- I understand that to an outside observer, the light from a star that is collapsing into a black hole will become more and more red-shifted as the surface of the star appears to approach the black hole event horizon. The outside observer will never actually see the surface of the star cross the black hole event horizon. This applies to all outside observers: at infinity, in orbit around the star/black hole or those using a rocket to hover above the black hole. Conversely, I know that for someone on the surface of the star that is collapsing to form a black hole it will appear quite different. The observer on the surface will not see anything unusual happen as they cross the event horizon and in a finite time they will reach the singularity at the center of the black hole where we do not know what will happen since general relativity breaks down in a singularity. So, now consider an observer that starts at a great distance from the star who is continually falling directly into the star…Imagine you are in an indestructible spaceship orbiting a black hole and you decide to launch a probe into the black hole. Explain how time would pass differently for you and the probe as it is pulled into the black hole. Also, explain what the onboard camera would observe as it passed the photon sphere and the event horizon.As a mass m of gas falls into a black hole, at most 0.1mc2 is likely to emerge as radiation; the rest is swallowed by the black hole. Show the Eddington luminosity for a black hole of mass M is equivalent to 2*10-9 Mc2yr-1. Explain why we expect the black hole's mass to grow by at least a factor of e every 5*107 years. Where Edding Luminicity is defined as LE=(4piGMmpc)/(sigmaT), where G is the gravitational constant, M is the mass of the black hole, mp is the mass of a proton, c is the speed of light, and sigmaT is Thomson scattering where sigmaT=6.653*10-25 cm2.
- Which of the following statements best describes the behaviour of an object falling towards the Event Horizon of a Black Hole (according to an observer a long way from it)? As gravity increases the falling object will not suffer any change in appearence or the progression of time. As gravity increases the object's light will be compressed, leading to it looking bluer, with time appearing to passing more slowly for it. The falling object will appear to experience an increase in the rate of time, and it's colour will appear evermore red. As the falling object experiences ever stronger gravity, it will become redder and time will appear to pass more slowly for it.The area of the event Horizon of a black hole is 4tRg². Use the Schwarzschild metric to verify this. (Please answer in detail or skip)Calculate the gravitational redshift of radiation of wavelength 550 nm (the middle of the visible range) that is emitted from a neutron star having a mass of 5.8 × 10³⁰ kg and a radius of 10 km. Assume that the radiation is being detected far from the neutron star.