An x polarized uniform plane wave travelling in z direction undergoes reflection thus the electric field of the standing wave is represented as Ex = Ae*jkz + Ce+jkz¸ The phase velocity of the wave is given by: %3D (A) vp = 1/veµ (A -C)/(A +C) cos2kz (B) vp = 1/veµ [(A -C)/(A +C) cos2kz + (A+C)/(A-C)sin2kz)] (C) vp =1/Veµ (A -C)/(A +C) sin2kz (D) vp = 1/Veµ (A -C)/(A +C) tan2kz.
An x polarized uniform plane wave travelling in z direction undergoes reflection thus the electric field of the standing wave is represented as Ex = Ae*jkz + Ce+jkz¸ The phase velocity of the wave is given by: %3D (A) vp = 1/veµ (A -C)/(A +C) cos2kz (B) vp = 1/veµ [(A -C)/(A +C) cos2kz + (A+C)/(A-C)sin2kz)] (C) vp =1/Veµ (A -C)/(A +C) sin2kz (D) vp = 1/Veµ (A -C)/(A +C) tan2kz.
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![An x polarized uniform plane wave travelling in z direction
undergoes reflection thus the electric field of the standing
wave is represented as Ex = Ae*Ikz + Ce*jkz, The phase velocity
of the wave is given by:
%3D
(A) vp = 1/Veµ (A -C)/(A +C) cos2kz
(B) vp = 1/veµ [(A -C)/(A +C) cos2kz + (A+C)/(A-C)sin2kz)]
%3D
(C) vp =1/Veµ (A -C)/(A +C) sin2kz
(D) vp = 1/Veµ (A -C)/(A +C) tan2kz.
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7d9fb55f-6ebc-4683-bd80-7e34affb6611%2F568bf4f1-4b70-42c3-a98c-bcbce9b759eb%2Frfwdc0k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:An x polarized uniform plane wave travelling in z direction
undergoes reflection thus the electric field of the standing
wave is represented as Ex = Ae*Ikz + Ce*jkz, The phase velocity
of the wave is given by:
%3D
(A) vp = 1/Veµ (A -C)/(A +C) cos2kz
(B) vp = 1/veµ [(A -C)/(A +C) cos2kz + (A+C)/(A-C)sin2kz)]
%3D
(C) vp =1/Veµ (A -C)/(A +C) sin2kz
(D) vp = 1/Veµ (A -C)/(A +C) tan2kz.
%3D
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