may heip you calculate the area). Insert below a screen shot of the simulation for above description and your worksheet which shows how you obtain final answer for each question Chats 39 seconds Velocity 120- a. What was the distance covered? m b. What is the area under the velocity curve? m c. What was the displacement of the man? m d. What was the speed of the man? (Remember speced distance traveled/given time interval) m/s e. What was the velocity? (Remember velocity = displacement/given time interval) m/s and direction (if any)

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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Velocity vs Time Graph Analysis**

In this exercise, we'll explore how the area under a velocity vs time graph correlates to the distance traveled along a straight line:

**Key Concepts:**

- **Displacement** = final position - initial position
- **Distance**: The actual path traveled.
- **Average velocity formula**:  
  \[
  \text{Average velocity} = \frac{\text{displacement (distance traveled along a straight line)}}{\text{given time interval}}
  \]

- **Velocity and distance formulas**:  
  \[
  v = \frac{a}{t} 
  \]  
  \[
  d = vt
  \]

**Instructions for the Activity:**

1. Set the initial position of the man at -10.0 m, the velocity at 5 m/s, and the acceleration at 0.0.
2. Run the simulation until the Moving Man reaches the wall.
3. Calculate the area under the velocity curve at the +10 m mark. This area will be between the velocity curve and the horizontal time axis.

**Illustrative Screenshot Description:**

The simulation shown in the screenshot features a graph with time on the horizontal axis (x-axis) and velocity on the vertical axis (y-axis). The Moving Man simulation is visually represented beside the graph. A line graph extends from the vertical axis, reflecting changes in velocity over time.

**Worksheet Questions:**

a. What was the distance covered? _______ m

b. What is the area under the velocity curve? _______ m

c. What was the displacement of the man? _______ m

d. What was the speed of the man? (Remember speed = distance traveled/given time interval) _______ m/s

e. What was the velocity of the man? (Remember velocity = displacement/given time interval) _______ m/s and direction (if any) _______

This exercise helps visualize the relationship between graphical area and physical distance, enhancing comprehension of velocity-time dynamics.
Transcribed Image Text:**Velocity vs Time Graph Analysis** In this exercise, we'll explore how the area under a velocity vs time graph correlates to the distance traveled along a straight line: **Key Concepts:** - **Displacement** = final position - initial position - **Distance**: The actual path traveled. - **Average velocity formula**: \[ \text{Average velocity} = \frac{\text{displacement (distance traveled along a straight line)}}{\text{given time interval}} \] - **Velocity and distance formulas**: \[ v = \frac{a}{t} \] \[ d = vt \] **Instructions for the Activity:** 1. Set the initial position of the man at -10.0 m, the velocity at 5 m/s, and the acceleration at 0.0. 2. Run the simulation until the Moving Man reaches the wall. 3. Calculate the area under the velocity curve at the +10 m mark. This area will be between the velocity curve and the horizontal time axis. **Illustrative Screenshot Description:** The simulation shown in the screenshot features a graph with time on the horizontal axis (x-axis) and velocity on the vertical axis (y-axis). The Moving Man simulation is visually represented beside the graph. A line graph extends from the vertical axis, reflecting changes in velocity over time. **Worksheet Questions:** a. What was the distance covered? _______ m b. What is the area under the velocity curve? _______ m c. What was the displacement of the man? _______ m d. What was the speed of the man? (Remember speed = distance traveled/given time interval) _______ m/s e. What was the velocity of the man? (Remember velocity = displacement/given time interval) _______ m/s and direction (if any) _______ This exercise helps visualize the relationship between graphical area and physical distance, enhancing comprehension of velocity-time dynamics.
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