may heip you calculate the area). Insert below a screen shot of the simulation for above description and your worksheet which shows how you obtain final answer for each question Chats 39 seconds Velocity 120- a. What was the distance covered? m b. What is the area under the velocity curve? m c. What was the displacement of the man? m d. What was the speed of the man? (Remember speced distance traveled/given time interval) m/s e. What was the velocity? (Remember velocity = displacement/given time interval) m/s and direction (if any)
may heip you calculate the area). Insert below a screen shot of the simulation for above description and your worksheet which shows how you obtain final answer for each question Chats 39 seconds Velocity 120- a. What was the distance covered? m b. What is the area under the velocity curve? m c. What was the displacement of the man? m d. What was the speed of the man? (Remember speced distance traveled/given time interval) m/s e. What was the velocity? (Remember velocity = displacement/given time interval) m/s and direction (if any)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Velocity vs Time Graph Analysis**
In this exercise, we'll explore how the area under a velocity vs time graph correlates to the distance traveled along a straight line:
**Key Concepts:**
- **Displacement** = final position - initial position
- **Distance**: The actual path traveled.
- **Average velocity formula**:
\[
\text{Average velocity} = \frac{\text{displacement (distance traveled along a straight line)}}{\text{given time interval}}
\]
- **Velocity and distance formulas**:
\[
v = \frac{a}{t}
\]
\[
d = vt
\]
**Instructions for the Activity:**
1. Set the initial position of the man at -10.0 m, the velocity at 5 m/s, and the acceleration at 0.0.
2. Run the simulation until the Moving Man reaches the wall.
3. Calculate the area under the velocity curve at the +10 m mark. This area will be between the velocity curve and the horizontal time axis.
**Illustrative Screenshot Description:**
The simulation shown in the screenshot features a graph with time on the horizontal axis (x-axis) and velocity on the vertical axis (y-axis). The Moving Man simulation is visually represented beside the graph. A line graph extends from the vertical axis, reflecting changes in velocity over time.
**Worksheet Questions:**
a. What was the distance covered? _______ m
b. What is the area under the velocity curve? _______ m
c. What was the displacement of the man? _______ m
d. What was the speed of the man? (Remember speed = distance traveled/given time interval) _______ m/s
e. What was the velocity of the man? (Remember velocity = displacement/given time interval) _______ m/s and direction (if any) _______
This exercise helps visualize the relationship between graphical area and physical distance, enhancing comprehension of velocity-time dynamics.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fefd1da3f-cb32-49f3-8aa7-bea0cbc5b54f%2Ff032ca38-45b9-4faa-bd2f-0b3f7422a8db%2Ftmn7yi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Velocity vs Time Graph Analysis**
In this exercise, we'll explore how the area under a velocity vs time graph correlates to the distance traveled along a straight line:
**Key Concepts:**
- **Displacement** = final position - initial position
- **Distance**: The actual path traveled.
- **Average velocity formula**:
\[
\text{Average velocity} = \frac{\text{displacement (distance traveled along a straight line)}}{\text{given time interval}}
\]
- **Velocity and distance formulas**:
\[
v = \frac{a}{t}
\]
\[
d = vt
\]
**Instructions for the Activity:**
1. Set the initial position of the man at -10.0 m, the velocity at 5 m/s, and the acceleration at 0.0.
2. Run the simulation until the Moving Man reaches the wall.
3. Calculate the area under the velocity curve at the +10 m mark. This area will be between the velocity curve and the horizontal time axis.
**Illustrative Screenshot Description:**
The simulation shown in the screenshot features a graph with time on the horizontal axis (x-axis) and velocity on the vertical axis (y-axis). The Moving Man simulation is visually represented beside the graph. A line graph extends from the vertical axis, reflecting changes in velocity over time.
**Worksheet Questions:**
a. What was the distance covered? _______ m
b. What is the area under the velocity curve? _______ m
c. What was the displacement of the man? _______ m
d. What was the speed of the man? (Remember speed = distance traveled/given time interval) _______ m/s
e. What was the velocity of the man? (Remember velocity = displacement/given time interval) _______ m/s and direction (if any) _______
This exercise helps visualize the relationship between graphical area and physical distance, enhancing comprehension of velocity-time dynamics.
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