An unsymmetrical flexural member consists of a ½ x 12 top flange, a ½ x 7 bottom flange, and a 3/8 x 16 web. b.) If A572 Grade 50 is used, what is the plastic moment Mp for the horizontal plastic neutral axis (already answered) QUESTION: SHOW THE SOLUTION FOR GETTING THE y for the top and bottom flange and the web. NOT THE ȳ . and draw the figure for better understanding. SOLVE THE CIRCLED RED PARTS OF THE IMAGE.
An unsymmetrical flexural member consists of a ½ x 12 top flange, a ½ x 7 bottom flange, and a 3/8 x 16 web. b.) If A572 Grade 50 is used, what is the plastic moment Mp for the horizontal plastic neutral axis (already answered) QUESTION: SHOW THE SOLUTION FOR GETTING THE y for the top and bottom flange and the web. NOT THE ȳ . and draw the figure for better understanding. SOLVE THE CIRCLED RED PARTS OF THE IMAGE.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
An unsymmetrical flexural member consists of a ½ x 12 top flange, a ½ x 7 bottom flange, and a 3/8 x 16 web.
b.) If A572 Grade 50 is used, what is the plastic moment Mp for the horizontal plastic neutral axis (already answered)
QUESTION: SHOW THE SOLUTION FOR GETTING THE y for the top and bottom flange and the web. NOT THE ȳ . and draw the figure for better understanding. SOLVE THE CIRCLED RED PARTS OF THE IMAGE.
Transcribed Image Text:5.2-2
(a) Area above PNA = Area below PNA
12(1/2) + (-1/2)(3/8) = (1/2+16 − ÿ)(3/8) + 7(1/2)
ỹ = 5.17 in.
(b) To locate centroids of areas, take moments about plastic neutral axis. For area above
PNA,
Component
top fl
web
Sum
A
6.000
1.750
7.750
y
4.917
2.334
y = 5.167
Ay
29.50
4.085
33.59
Transcribed Image Text:1
=
ΣΑΥ 33.59
ΣΑ
7.750
For area below PNA,
www.w
* 4. 334 in.
Component
bot. fl
web
Sum
64.61
7.750
52
ΣΑy
ΣΑ
Plastic moment:
Mp = Cx moment arm Tx moment arm
= AF,G1 + 72) = 7.750(50)(4.334 + 8.337)
A
3.500
4.250
7.750
=
y
11.58
5.667
8. 337 in.
wwwww
= 387.5(12.67) = 4910 in-kips = 409 ft-kips
Ay
40.53
24.08
64.61
My = 409 ft-kips
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