An unknown polymer sample was found to have the following molecular weight distribution:Molecular weight range8,000 - 20,00020,000 - 32,00032,000 - 44,00044,000 - 56,00056,000 -68,00068,000 -80,00080,000 - 92,000Having a DP=763, which of the following common polymers is this sample?Xi0.050.150.210.280.180.100.03Wi0.020.080.170.290.230.160.05Select one:O a. Polymethylmethacrylate with a monomer molecular weight of 100.121 g/molO b.Polystyrene with a monomer molecular weight of 104.15 g/molPolycarbonate with a monomer molecular weight of 61.0168 g/molO c.O d.Polyvinyl chloride with a monomer molecular weight of 62.498 g/molPolypropylene with a monomer molecular weight of 42.08 g/molO e.

An unknown polymer sample was found to have the following molecular weight distribution: Molecular weight range 8,000 - 20,000 20,000 - 32,000 32,000 - 44,000 44,000 - 56,000 56,000-68,000 68,000 -80,000 80,000-92,000 X₁ 0.05 0.15 0.21 0.28 0.18 0.10 0.03 Wi 0.02 0.08 0.17 0.29 0.23 0.16 0.05

An unknown polymer sample was found to have the following molecular weight distribution: Molecular weight range 8,000 - 20,000 20,000 - 32,000 32,000 - 44,000 44,000 - 56,000 56,000-68,000 68,000 -80,000 80,000-92,000 X₁ 0.05 0.15 0.21 0.28 0.18 0.10 0.03 Wi 0.02 0.08 0.17 0.29 0.23 0.16 0.05

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Please written by hand
Calculate the modulus of rigidity (shear modulus) of an epoxy resin if the modulus of elasticity (Young's modulus) E = 3.5 GPa and the Poisson's ratio = 0.35. Select one: a. G = 2.6 GPa b. G = 10 GPa c. G = 3.15 GPa d. G= 0.1 GPa e. G = 1.3 GPa
Design and manufacture of plastic and composite parts The tank shown in Figure 1 is stacked as follows: Couches individuelles: verre = glass 1 - Unidirectionnel verre/epoxy, V₁ = 62%, h = 0.010 po. 2- Mat verre/epoxy, V₁ = 40%, h = 0.040 po. Extérieur 4 Empilement: [0/35/-35/90] 3 2 3 1 Intérieur Unidirectionnel kevlar-epoxy, V₁ = 55%, h = 0.010 po. 4- Tissus 50/50, Kevlar/epoxy, 230 g/m2, V₁ = 50% h = épaisseur du PLI V₁ = Pourcentage volumique de fibres As well as the following load and dimensions: P = 3 MPa r = 50 mm L = 625 mm h = 600 mm F = 500 N N h р B x F Figure 1. multilayer composite pipe under pressure (p), also subject to torsional moment and bending moment due to force F and lever arms h and L. page 1
Answer whats in the image, please and thank you
1. For the stress-strain curve shown below, please estimate the properties indicated. (a) Fracture Strain Please do your work on a separate sheet of paper, and put your answers in the boxes on the right. Be sure to include the proper symbol and units. Stress Strain 70 60 50 Stress (ksi) 240 30 20 10 70 0 0.000 60 50 Stress (ksi) 40 20 10 KULL 0 0.000 0.010 0.050 0.100 Strain (in/in) Stress Strain 0.020 0.030 Strain (in/in) 0.040 0.150 0.050 (b) Ultimate Tensile Stress (c) Fracture Stress (d) Proportional Limit (e) Elastic Modulus (1) Yield Stress (g) Tensile Toughness (Modulus of Toughness) (h) Modulus of Resilience
Q2: A fiberglass composite consists of a matrix of vinyl ester and reinforcing fibers of E-glass. The volume fraction of E-glass is 30%. The density of the vinyl estiser 0.882 g/cm³, and its modulus of elasticity is 3.6 GPa. The density of E-glass is 2.6 g/cm³, and its modulus of elasticity is 76 GPa. A section of composite 1 cm by 25 cm by 2 m is fabricated with the E-glass fibers running longitudinally in the 2000 mm direction. Determine: (a) The masses of vinyl ester and E-glass fibers. (b) The density of the composite. (c) The composite modulus of elasticity in the longitudinal and the perpendicular directions of the glass fibers. (d) If the tensile strength of the glass fibers, is 1 GPA and the tensile strength of the epoxy matrix is 60 MPa, find the tensile strength of the composite in the longitudinal direction.
A composite material consists of 60% glass fibre by volume (V₁ = 0.6). Half of the fibre is in unidirectional (0°) roving form and the other half is continuous fibre (0°, 90°) mat. The matrix is polyester. The properties of the constituent materials are shown in Table 4. Table 4 Density (Mg.m³) Tensile modulus (GPa) Tensile strength (MPa) Fibre 2.6 69 1200 i. Calculate the density of the composite material Matrix 1.1 2 35 ii. Calculate the tensile strength, oc, and the tensile modulus, Ec, of the composite in the 0° and 90° directions using the simple "rule of mixtures" approach.
d) A number of [0]s and [0,90]s CFRP test specimens were made from prepreg material with the following properties: Fibre strength, of = 3250 MPa Fibre modulus, E₁ = 195 GPa Matrix strength, m = 35 MPa Matrix modulus, Em = 3.8 GPa Volume fraction of fibres, Vf = 0.65 Calculate the tensile strength, oc, and the tensile modulus, Ec, in the 0° and 90° directions, using the simple "rule of mixtures" approach for both the [0]s and [0,90]s specimens.
A Tensile Tests of structural steel indicate that it fails whe the axial tensile strain is 1.80x10 μ. 3 Let maximum change in length that 0.25 [in] diamoren in tension car with stand before failure Length Find Structural Steel rad it It is 24 [in] in ni sa 9102
A composite material that has boron fibers coated in aluminum has a density of 2.65 g/cm^3. The fibers have a Young's modulus of 380 GPa, and aluminum has a Young's modulus of 70 GPa. The density of the fibers is 2.36 g/cm^3 and the density of the aluminum is 2.70 g/cm^3. What is the volume of the matrix? Answer:
The answer is one of the options below please solve carefully and circle the correct option Please write clear .
Questions d-f