An RLC series circuit is connect to a 135-V/150-Hz source (see the picture below). Given that L = 98 mH, C = 75 µF and R = 160 2, find the rms current in the circuit and rms voltage drop across each element. L C V The current, Irms = 0.75 www R ✔Unit A The voltage drop across L, (VL)rms The voltage drop across C, (Vc)rms The power dissipation, P = 74 = 70 = 10 Unit V X Unit V The voltage drop across R, (VR)rms 120 Find the phase shift and the power dissipated in the circuit. The phase shift, = 0.45 ✓Unit V x Unit Select an answer x Unit Select an answer
An RLC series circuit is connect to a 135-V/150-Hz source (see the picture below). Given that L = 98 mH, C = 75 µF and R = 160 2, find the rms current in the circuit and rms voltage drop across each element. L C V The current, Irms = 0.75 www R ✔Unit A The voltage drop across L, (VL)rms The voltage drop across C, (Vc)rms The power dissipation, P = 74 = 70 = 10 Unit V X Unit V The voltage drop across R, (VR)rms 120 Find the phase shift and the power dissipated in the circuit. The phase shift, = 0.45 ✓Unit V x Unit Select an answer x Unit Select an answer
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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#### Results:
1. **The RMS Current, \( I_{\text{rms}} \)**
\[
I_{\text{rms}} = 0.75 \, \text{A}
\]
2. **The Voltage Drop Across the Inductor, \( (V_L)_{\text{rms}} \)**
\[
(V_L)_{\text{rms}} = 70 \, \text{V}
\]
3. **The Voltage Drop Across the Capacitor, \( (V_C)_{\text{rms}} \)**
\[
(V_C)_{\text{rms}} = 10 \, \text{V}
\]
4. **The Voltage Drop Across the Resistor, \( (V_R)_{\text{rms}} \)**
\[
(V_R)_{\text{rms}} = 120 \, \text{V}
\]
#### Additional Parameters:
- **The Phase Shift \( \phi \) and Power Dissipation \( P \) in the Circuit:**
- **Phase Shift, \( \phi \)**
\[
\phi = 0.45 \, \text{radians} \quad (\text{Incorrect -- this needs review})
\]
- **Power Dissipation, \( P \)**
\[
P = 74 \, \text{W} \quad (\text{Incorrect -- this needs review})
\]
The current values for phase shift and power dissipation seem to need verification as they are marked incorrect. This indicates further analysis or calculation might be required.
### Explanation of the Circuit Diagram
The circuit diagram shows:
- **L (Inductor)**: Part of the series circuit.
- **](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa90f48aa-fe1f-4446-8e54-ba82906f66bc%2F82525b0b-d114-4e28-a50c-f2ccb1a41d45%2F35vzx57_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### RLC Circuit Analysis
An RLC series circuit is connected to a 135-V/150-Hz source as depicted in the diagram below. Given the following component values:
- Inductance, \( L = 98 \, \text{mH} \)
- Capacitance, \( C = 75 \, \mu\text{F} \)
- Resistance, \( R = 160 \, \Omega \)
We aim to find the RMS current in the circuit and the RMS voltage drop across each element.

#### Results:
1. **The RMS Current, \( I_{\text{rms}} \)**
\[
I_{\text{rms}} = 0.75 \, \text{A}
\]
2. **The Voltage Drop Across the Inductor, \( (V_L)_{\text{rms}} \)**
\[
(V_L)_{\text{rms}} = 70 \, \text{V}
\]
3. **The Voltage Drop Across the Capacitor, \( (V_C)_{\text{rms}} \)**
\[
(V_C)_{\text{rms}} = 10 \, \text{V}
\]
4. **The Voltage Drop Across the Resistor, \( (V_R)_{\text{rms}} \)**
\[
(V_R)_{\text{rms}} = 120 \, \text{V}
\]
#### Additional Parameters:
- **The Phase Shift \( \phi \) and Power Dissipation \( P \) in the Circuit:**
- **Phase Shift, \( \phi \)**
\[
\phi = 0.45 \, \text{radians} \quad (\text{Incorrect -- this needs review})
\]
- **Power Dissipation, \( P \)**
\[
P = 74 \, \text{W} \quad (\text{Incorrect -- this needs review})
\]
The current values for phase shift and power dissipation seem to need verification as they are marked incorrect. This indicates further analysis or calculation might be required.
### Explanation of the Circuit Diagram
The circuit diagram shows:
- **L (Inductor)**: Part of the series circuit.
- **
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