An AC sine wave with an RMS value of 120VAC is connected to a full-wave rectifier. What is the average DC voltage O 169 VDC O 108 VDC O 108.068 VAC O none of the above
An AC sine wave with an RMS value of 120VAC is connected to a full-wave rectifier. What is the average DC voltage O 169 VDC O 108 VDC O 108.068 VAC O none of the above
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Question:**
An AC sine wave with an RMS value of 120 VAC is connected to a full-wave rectifier. What is the average DC voltage?
**Options:**
- ○ 169 VDC
- ● 108 VDC
- ○ 108.068 VAC
- ○ none of the above
**Explanation:**
The question asks for the average DC voltage when an AC sine wave with an RMS value of 120 VAC is connected to a full-wave rectifier. To calculate this, use the formula for the average DC voltage (V_avg) of a full-wave rectified sine wave, which is:
\[ V_{\text{avg}} = \frac{2 \times V_{\text{peak}}}{\pi} \]
where \( V_{\text{peak}} \) is the peak voltage given by:
\[ V_{\text{peak}} = V_{\text{RMS}} \times \sqrt{2} \]
Therefore:
1. Calculate the peak voltage:
\[ V_{\text{peak}} = 120 \times \sqrt{2} \approx 169.71 \text{ V} \]
2. Calculate the average DC voltage:
\[ V_{\text{avg}} = \frac{2 \times 169.71}{\pi} \approx 108 \text{ VDC} \]
Thus, the correct answer is 108 VDC.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45694c89-08dc-4cba-91a1-85b08f29da35%2F8695cfce-fca8-44a9-9708-01b9b88ef352%2F4oi8r9f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question:**
An AC sine wave with an RMS value of 120 VAC is connected to a full-wave rectifier. What is the average DC voltage?
**Options:**
- ○ 169 VDC
- ● 108 VDC
- ○ 108.068 VAC
- ○ none of the above
**Explanation:**
The question asks for the average DC voltage when an AC sine wave with an RMS value of 120 VAC is connected to a full-wave rectifier. To calculate this, use the formula for the average DC voltage (V_avg) of a full-wave rectified sine wave, which is:
\[ V_{\text{avg}} = \frac{2 \times V_{\text{peak}}}{\pi} \]
where \( V_{\text{peak}} \) is the peak voltage given by:
\[ V_{\text{peak}} = V_{\text{RMS}} \times \sqrt{2} \]
Therefore:
1. Calculate the peak voltage:
\[ V_{\text{peak}} = 120 \times \sqrt{2} \approx 169.71 \text{ V} \]
2. Calculate the average DC voltage:
\[ V_{\text{avg}} = \frac{2 \times 169.71}{\pi} \approx 108 \text{ VDC} \]
Thus, the correct answer is 108 VDC.
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