An overhanging beam is subjected to a partial uniform load w = 23 kN/m and two pint loads P1 = 60 kN, P2 =436 kN. The beam has a hinge support at point B, a horizontal roller support at point A with overhangs on both sides as shown. ← P1 (kN) 3 m AD w (kN/m) 5 m P2 (KN) 2 m 7AB 2 m What is the absolute maximum bending moment in kN-m anywhere on the beam? NOTE: ONLY ENTER ABSOLUTE VALUES. For example: if you calculate a max positive moment = 652 and a max negative moment = -450 kN-m, you would enter 652 if you calculate a max positive moment = 333 and a max negative moment = -485 kN-m, you would enter 485

An overhanging beam is subjected to a partial uniform load w = 23 kN/m and two pint loads P1 = 60 kN, P2 =436 kN. The beam has a hinge support at point B, a horizontal roller support at point A with overhangs on both sides as shown. ← P1 (kN) 3 m AD w (kN/m) 5 m P2 (KN) 2 m 7AB 2 m What is the absolute maximum bending moment in kN-m anywhere on the beam? NOTE: ONLY ENTER ABSOLUTE VALUES. For example: if you calculate a max positive moment = 652 and a max negative moment = -450 kN-m, you would enter 652 if you calculate a max positive moment = 333 and a max negative moment = -485 kN-m, you would enter 485

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

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An overhanging beam is subjected to a partial uniform load w = 23 kN/m and two pint loads P1 =
60 kN, P2 =436 kN. The beam has a hinge support at point B, a horizontal roller support at point A
with overhangs on both sides as shown.
←
P1 (kN)
3 m
AD
w (kN/m)
5m
P2 (KN)
2 m
7AB
2 m
What is the absolute maximum bending moment in kN-m anywhere on the beam? NOTE: ONLY
ENTER ABSOLUTE VALUES.
For example:
if you calculate a max positive moment = 652 and a max negative moment = -450 kN-m, you would
enter 652
if you calculate a max positive moment = 333 and a max negative moment = -485 kN-m, you
would enter 485

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