An overhanging beam is subjected to a partial uniform load w = 23 kN/m and two pint loads P1 = 60 kN, P2 =436 kN. The beam has a hinge support at point B, a horizontal roller support at point A with overhangs on both sides as shown. ← P1 (kN) 3 m AD w (kN/m) 5 m P2 (KN) 2 m 7AB 2 m What is the absolute maximum bending moment in kN-m anywhere on the beam? NOTE: ONLY ENTER ABSOLUTE VALUES. For example: if you calculate a max positive moment = 652 and a max negative moment = -450 kN-m, you would enter 652 if you calculate a max positive moment = 333 and a max negative moment = -485 kN-m, you would enter 485
An overhanging beam is subjected to a partial uniform load w = 23 kN/m and two pint loads P1 = 60 kN, P2 =436 kN. The beam has a hinge support at point B, a horizontal roller support at point A with overhangs on both sides as shown. ← P1 (kN) 3 m AD w (kN/m) 5 m P2 (KN) 2 m 7AB 2 m What is the absolute maximum bending moment in kN-m anywhere on the beam? NOTE: ONLY ENTER ABSOLUTE VALUES. For example: if you calculate a max positive moment = 652 and a max negative moment = -450 kN-m, you would enter 652 if you calculate a max positive moment = 333 and a max negative moment = -485 kN-m, you would enter 485
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter5: Stresses In Beams (basic Topics)
Section: Chapter Questions
Problem 5.5.27P: A small dam of a height h = 6 ft is constructed of vertical wood beams AB, as shown in the figure....
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![An overhanging beam is subjected to a partial uniform load w = 23 kN/m and two pint loads P1 =
60 kN, P2 =436 kN. The beam has a hinge support at point B, a horizontal roller support at point A
with overhangs on both sides as shown.
←
P1 (kN)
3 m
AD
w (kN/m)
5m
P2 (KN)
2 m
7AB
2 m
What is the absolute maximum bending moment in kN-m anywhere on the beam? NOTE: ONLY
ENTER ABSOLUTE VALUES.
For example:
if you calculate a max positive moment = 652 and a max negative moment = -450 kN-m, you would
enter 652
if you calculate a max positive moment = 333 and a max negative moment = -485 kN-m, you
would enter 485](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7706bd66-a98f-4a85-bf68-9e0a43a23cd0%2F19e7d244-e736-4c68-87a5-f34d5dcc1d7a%2Fznq0b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:An overhanging beam is subjected to a partial uniform load w = 23 kN/m and two pint loads P1 =
60 kN, P2 =436 kN. The beam has a hinge support at point B, a horizontal roller support at point A
with overhangs on both sides as shown.
←
P1 (kN)
3 m
AD
w (kN/m)
5m
P2 (KN)
2 m
7AB
2 m
What is the absolute maximum bending moment in kN-m anywhere on the beam? NOTE: ONLY
ENTER ABSOLUTE VALUES.
For example:
if you calculate a max positive moment = 652 and a max negative moment = -450 kN-m, you would
enter 652
if you calculate a max positive moment = 333 and a max negative moment = -485 kN-m, you
would enter 485
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