An open glass tube of uniform cross-section is bent into the shape of an L. One arm is immersed in a liquid of density p, and the other arm of length / remains in the air in a horizontal position. The tube is rotated with constant angular speed w about the axis of the vertical arm. Prove that the height y to which the liquid rises in the vertical arm is equal to Po(1 – eLM/2RT) y = where Po is atmospheric pressure, M is the molar mass of air, and g is the accelera- tion of gravity.

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An open glass tube of uniform cross-section is bent into the shape of an L. One arm is
immersed in a liquid of density p, and the other arm of length / remains in the air in a
horizontal position. The tube is rotated with constant angular speed w about the axis
of the vertical arm. Prove that the height y to which the liquid rises in the vertical arm
is equal to
Po(1 – eLM/2RT)
y =
where Po is atmospheric pressure, M is the molar mass of air, and g is the accelera-
tion of gravity.
Transcribed Image Text:An open glass tube of uniform cross-section is bent into the shape of an L. One arm is immersed in a liquid of density p, and the other arm of length / remains in the air in a horizontal position. The tube is rotated with constant angular speed w about the axis of the vertical arm. Prove that the height y to which the liquid rises in the vertical arm is equal to Po(1 – eLM/2RT) y = where Po is atmospheric pressure, M is the molar mass of air, and g is the accelera- tion of gravity.
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