An online grocery company is researching the best location to start their new delivery service. They are comparing two local regions, A and B. In a random sample of 505 residents in region A, 26.1% said that they would use an online grocery store. In a random sample of 388 residents in region B, 29.5% said they would use an online grocery store. Find a 95% confidence interval for the difference in the proportions of residents in these two regions who would use an online grocery store. The CEO believes that region B will have a higher proportion of potential customers than region A. Does your confidence interval support that conclusion? Explain.

Q: 1) A sample of 532 Peanut Butter M&M's contains 74 yellow candies; write a 95% confidence statement…

A: In this case, the confidence level is 95%. The 95% confidence interval for the proportion/percentage…

Q: 3- Car and Driver Magazine tested a random sample of 9 hybrid cars and found their MPG to be 42, 51,…

A:

Q: A local newspaper in a large city wants to assess support for the construction of a highway bypass…

A: given that,possible chances (x)=543size(n)=1152success rate ( p )= x/n = 0.4714point of estimate =…

Q: A sports news station wanted to know whether people who live in the North or the South are bigger…

A:

Q: In a random sample of 100 customers, the items that customers purchased were tracked. It was found…

A: Given,sample size(n)=100sample proportion(p^)=0.171-p^=1-0.17=0.83α=1-0.90=0.1α2=0.05Z0.05=1.645

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: It is given that, x is 311 and n is 400.

Q: knowing

A: Given: Total number of drivers = 383 Drivers who buckle up = 297 Proportion of drivers, p =…

Q: A class has 420 students. The final examination is optional—taking it can raise, but cannot lower, a…

A: It is given that sample size (n) is 80 and the number of students would take the final examination…

Q: In a recent Dew Research Poll, 500 U.S. adults were asked about their online versus in-store clothes…

A:

Q: A poll reported 38% support for a statewide election with a margin of error of 1.36 percentage…

A: Proportion of voters who supports for a statewide election Margin of error Confidence level

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: Solution

Q: In a recent survey of 200 households, 172 had central air conditioning.  Find the 85% confidence…

A: Given that In a recent survey of 200 households, 172 had central air conditioning That is…

Q: A researcher was interested in knowing how many people in the city supported a new tax. She sampled…

A:

Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…

A: It is given that the proportion of the students who preferred a quarter system to a trimester…

Q: In a survey of 612 randomly selected female college students, 141 report that they had been sexually…

A: Given Information:n=612x=141c=95%=0.95

Q: In a sample of 500 Canadians, 275 say they would rather retire in the US than in Canada. Calculate…

A:

Q: In a survey of 50,00 people, 80% indicated that they listened to their favorite radio station…

A: Hern= 5000 P^ = 0.80 We have to construct 95% ci for p

Q: In a survey of 2255 randomly selected US adults (age 18 or older), 1787 of them use the Internet…

A: We want to calculate the 90% confidence interval for each of the following proportions

Q: qualities as options, one of which is "communicator", as the most important quality for an effective…

A: It is given that  Favourable cases, X = 121 Sample size, n = 275 Sample proportion, p^ = X/n…

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: a newspaper article stated that the us supreme court received 812 letters from around the country on…

A: To find the 95% confidence interval for the true proportion of all American adults who feel that…

Q: n a randomly selected group of 750 automobile deaths, 240 were alcohol related. Construct a 95%…

A: Given that,  x = 240, n = 750 The value of sample proportion is,

Q: in a random sample of 60 students from a very large university, only 25% were able to identify…

A: Given Sample size n=60, sample proportion p^=0.25  Construct 95% CI for population proportion p

Q: andom sample of 1200 high school freshmen was taken and it was found that 559 of them were reading…

A: The population proportion (p) will be proportion of high school freshman who reads at or above their…

Q: An insurance company collects data on seat-belt use among drivers in a country. Of 1100 drivers…

A: We have given two age groups of drivers and an insurance company collects data on seat-belt use…

Q: 7 out of 70 students said they were comfortable with “working in a workplace with a lot of…

A: Given that  57 out of 70 students said they were comfortable with “working in a workplace with a lot…

Q: In a random sample of 575 American goods, about 46.3% of them were transported by rail in 2017.…

A: Given,   Sample size = 575 Sample proportion = 0.463   Critical value: Using z-table, the z-critical…

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: Given that, X = 118 N = 200 99% confidence level

Q: In a survey of 1,626,773 U.S. adults, 49,311 personally identified as lesbian, gay, bisexual, or…

A:

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: Givenx=316sample size(n)=391Confidence level=95%p^=xn=316391≅0.8082

Q: in a random sample of 192 college students, 129 had part-time jobs. Find the margin of error for the…

A:

Q: As health insurance costs and the number of disabled employees increase, more companies are firing…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: Insurance companies are interested in knowing the popul drivers who always buckle up before riding…

A: Given data,No of people surveyed n=387who claims to buckle up is x=311Construct a 93 % CI?

Q: In a random sample of 184 college students, 97 had part-time jobs. Find the margin of error for the…

A: Given : Sample Size, n = 184 Number of successes, x = 97 confidence level,c=0.99

Q: A genealogist randomly selected 203 Americans and asked about their heritage. Of those randomly…

A:

Q: A random sample of 400 people is selected from Atlantic Canada. They are asked about their views on…

A: According to the given information, we have Given that a random sample of 400 people is selected…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.