An old copper cup (Figure 3) of mass 50.0 g is filled with 251 g of water. Both the cup and water are in thermal equilibrium i.e., they are at temperature 90.0 °C. Some ice of mass 25.1 g and at 0.00 °C is added to the water and then the cup is insulated so no heat can escape. After some time, the ice melts and the system eventually reaches a new equilibrium temperature x. • Specific Heat Capacity of Copper = 380 J kg1 K1 • Specific Heat Capacity of Liquid Water =4180 J kg1 K1 • Latent Heat of Fusion for Water = 334 x 10° J kg1 • Latent Heat of Vaporization for Water = 2260 x 103 J kg1 Figure 3 i) What is meant by thermal equilibrium? ii) While insulated the water, ice and copper will either gain or lose heat energy before reaching thermal equilibrium. State which gains and which loses energy. iii) Find an expression in terms of x for the change in heat energy of the copper,
An old copper cup (Figure 3) of mass 50.0 g is filled with 251 g of water. Both the cup and water are in thermal equilibrium i.e., they are at temperature 90.0 °C. Some ice of mass 25.1 g and at 0.00 °C is added to the water and then the cup is insulated so no heat can escape. After some time, the ice melts and the system eventually reaches a new equilibrium temperature x. • Specific Heat Capacity of Copper = 380 J kg1 K1 • Specific Heat Capacity of Liquid Water =4180 J kg1 K1 • Latent Heat of Fusion for Water = 334 x 10° J kg1 • Latent Heat of Vaporization for Water = 2260 x 103 J kg1 Figure 3 i) What is meant by thermal equilibrium? ii) While insulated the water, ice and copper will either gain or lose heat energy before reaching thermal equilibrium. State which gains and which loses energy. iii) Find an expression in terms of x for the change in heat energy of the copper,
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