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What mass of steam at 100°C must be mixed with 150 g of ice at -10°C, in a thermally insulated container, to produce liquid water at 50°C? Data: L = 2256 kJ/kg L = 333 kJ/kg Cw = 4190 J/kg.K Cice = 2220 J/kg•K ** %3D

What mass of steam at 100°C must be mixed with 150 g of ice at -10°C, in a thermally insulated container, to produce liquid water at 50°C? Data: L = 2256 kJ/kg L = 333 kJ/kg Cw = 4190 J/kg.K Cice = 2220 J/kg•K ** %3D

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What mass of steam at 100°C must be mixed with 150 g of ice at -10°C, in a thermally insulated container, to produce liquid water at 50°C? Data: Ly = 2256 kJ/kg L = 333 kJ/kg Cw = 4190 J/kg-K Cice = 2220 J/kg•K **
Transcribed Image Text:What mass of steam at 100°C must be mixed with 150 g of ice at -10°C, in a thermally insulated container, to produce liquid water at 50°C? Data: Ly = 2256 kJ/kg L = 333 kJ/kg Cw = 4190 J/kg-K Cice = 2220 J/kg•K **
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