An oil tank is connected to a pressure gage through a double-U manometer, as shown in the picture below. The reading of the pressure gage of the oil tank at the point J is P,- 250 kPa, all liquids (water, oil, and mercury) are incompressible: The effect of air column on pressure is negligible. Determine the gage pressure [kPa] at the point A (PA???). (Note: the density of water to be pw oil and mercury are 0.88 and 13.6, respectively) 1000 kg/m³; take the gravity g-9.81 m/s²; the specific gravities of

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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An oil tank is connected to a pressure gage through a double-U manometer, as shown in the
picture below. The reading of the pressure gage of the oil tank at the point J is P,- 250 kPa, all liquids
(water, oil, and mercury) are incompressible: The effect of air column on pressure is negligible. Determine
the gage pressure [kPa] at the point A (PA???).
(Note: the density of water to be pw 1000 kg/m³; take the gravity g-9.81 m/s²; the specific gravities of
oil and mercury are 0.88 and 13.6, respectively)
A
10 cm
Air
50 cm
60%
Water
C
D
40 cm
E
Air
Mercury
15 cm
G
Oil
P-250 kPa
50 cm
BUS
Transcribed Image Text:An oil tank is connected to a pressure gage through a double-U manometer, as shown in the picture below. The reading of the pressure gage of the oil tank at the point J is P,- 250 kPa, all liquids (water, oil, and mercury) are incompressible: The effect of air column on pressure is negligible. Determine the gage pressure [kPa] at the point A (PA???). (Note: the density of water to be pw 1000 kg/m³; take the gravity g-9.81 m/s²; the specific gravities of oil and mercury are 0.88 and 13.6, respectively) A 10 cm Air 50 cm 60% Water C D 40 cm E Air Mercury 15 cm G Oil P-250 kPa 50 cm BUS
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