An oil of sp. gr. 0.9 is flowing through a venturimeter having inlet diameter 20 cm and throat diameter 10 cm. The oil-mercury differential manometer shows a reading of 20 cm. Calculate the discharge of oil through the horizontal venturimeter. Take C = 0.98. [Ans. 59.15 litres/s]

Fundamental of fluid flow: A venturi meter with a throat diameter of 6 cm is fitted in a horizontal pipeline of 12 cm diameter with oil of specific gravity 0.88 flowing from left to the right. The difference in level in the two limbs of a mercury manometer connected to the tapping points read 12 cm and the connecting pipes are filled with the same oil. (a) If two pressure gauges are fitted at tapping points, one at the throat and the other in the inlet. Determine the difference between the 2 gage pressure readings in kPa. (b) Determine the flow in m^3/s neglecting head losses.

Gentlemen, please check and help me with question #3 Tank filled with water and orifice diameter of 3 cm in the bottom. Height between centre of orifice and water level 3 m. Coefficient of discharge - 0.64, coefficient of velocity- 0.97.  Find: 1. Actual jet velocity? This one I know how to do. V(actual) = square root from 2gH 2. Jet diameter? This one I know as well. Coefficient of contraction= coefficient of discharge/ coefficient of velocity  Diam of jet we will find from formula: Coefficient of contraction = (diameter of jet/diameter of orifice)^2 3. How long will it take for jet to be established?