An observer to the right of the mirror-lens combination shown below sees two real images that are the same size and in the same location. Both images are 1.50 times larger than the object. The lens has a focal length of 8.0 cm. The lens and mirror are separated by 44.0 cm. Determine the focal length of the mirror. The inverted image occurs when the light from the object passes directly through the lens. The upright image occurs when the light from the object bounces off the mirror first, and then passes through the lens. Mirтor Lens Images Object
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- Two lenses are separated by 50 cm. Lens 1 is convex and has a radius of curvature of magnitude 30 cm. Lens 2 is concave and has a radius of curvature of magnitude 40 cm and is located to the right of Lens 1. An object is located 20 cm to left of lens 1. Find the location of the final image of the object. What is the magnification of the final image?A tall tree is growing across a river from you. You would like to know the distance between yourself and the tree,as well as its height, but are unable to make the measurements directly. However, by using a mirror to form an image of the tree and then measuring the image distance and the image height, you can calculate the distance to the tree as well as its height. Suppose that this mirror produces an image of the sun, and the image is located 0.8646 m from the mirror. The same mirror is then used to produce an image of the tree. The image of the tree is 0.9468 m from the mirror. (a) How far away is the tree? (b) The image height of the tree has a magnitude of 0.15 m. How tall is the tree?An object is 60.0 cm from a converging lens and the object is 1.00 cm tall. What is the poisition and height of the image if the focal length of the lens is 25.0 cm? The object is at 0.0233 cm and the height of the image will be 0.715 cm upright. The object is at 0.0233 cm and the height of the image will be 0.000388 cm inverted. The object is at 42.9 cm and the height of the image will be 0.000388 cm upright. The object is at 42.9 cm and the height of the image will be 0.715 cm inverted.
- A person looks at a gem using a converging lens with a focal length of 13.8 cm. The lens forms a virtual image 33.1 cm from the lens. Find the magnification. Describe the image. 1. real, upright, larger 2. real, inverted, larger 3. virtual, upright, larger 4. real, inverted, smaller 5. virtual, inverted, larger 6. real, upright, smaller 7. virtual, inverted, smaller 8. virtual, upright, smallerFamous jeweler Gabi Tolkowsky is looking at a 3.0-cm-tall perfect oval-shaped diamond through a thin lens. The diamond is 20.0 cm behind the lens, and the distance between its upright image and the lens is 40.0 cm. What is the focal length of the lens? Is it converging or diverging? How tall is the image? PLEASE PLEASE draw a ray diagram and define variablesA room in an amusement park funhouse has two flat mirrors on opposite walls, so that a person standing between the mirrors sees a "never-ending" series of reflections. A person stands 2.40 m from the mirror on the left wall and 5.50 m from the mirror on the right wall. What are the distances (in m), as measured from the person, for the first three images seen by the person in the left wall mirror? first image second image third image 2.40 X This is the image distance from the left mirror. Add this to the distance from the person to the mirror to get the total distance from the person to the image. m m m
- Two light rays originate from object A, at a distance of 50 cm in front of a flat mirror, diverging at an angle of 10°. Both of the rays strike a flat mirror and reflect. Two light rays originate from object B, at a distance of 50 cm in front of a convex mirror, diverging at an angle of 10°. Both of the rays strike the convex mirror and reflect. For which object do the reflected rays appear to converge behind the mirror closer to the surface of the mirror, thus forming a closer (larger) image? Explain with the help of a sketch or diagram.A 4 cm tall light bulb is placed a distance of 35.5 cm from a diverging lens whose focal length magnitude is 12.2 cm. Determine the image distance from the lens, the image height, and the magnification. Put into words what your calculations physically represent about the image.A man standing 1.54 m in front of a shaving mirror produces an inverted image 18.6 cm in front of it. How close to the mirror should he stand if he wants to form an upright image of his chin that is twice the chin's actual size? cm A contact lens is made of plastic with an index of refraction of 1.40. The lens has an outer radius of curvature of +1.92 cm and an inner radius of curvature of +2.47 cm. What is the focal length of the lens? cm