An object was displaced by a position dependent force. In universel, theforce is a piece-wise function of posi tion, while in universe II, the force is alinearfunction of posi tion. Which is the correct relationship between F1 andF2 so that the network done in is equal to that of ?Universe IUniverse IIF,F,x(m)x(m2.1010F1=F22F1=F2O F1=2F2O 2F1=F2

Answered: Image /qna-images/answer/5a1d0a32-a4c3-4982-a073-2d6eb11f62af.jpg

Answered: An object was displaced by a position…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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4. Using symmetry on the frame shown below, solve for the unknown displacements and rotations. When setting up the stiffness matrix you may neglect terms that would be used to find the reactions. Use a consistent unit system from the table below. Note, the connections at nodes 2 and 4 are pins that do not allow X andY displacements but do allow rotations. 60 kN 6 m 6 m E- 210 GPa | - 1.0 x 10m A - 1.0 x 10-m 100 kN-m 100 kNm 6 m Consistent Units MASS LENGTH TIME FORCE STRESS
In the study of the Lagrangian mechanics, a system of particles imply: A. One particle/object involved in the problem B. If more than one particle/object are involved, then they interact with one another c. If more than one particle are involved, then they do not interact with one another D. A and B are correct E. A and C are correct F. None of the above is correct
Explain the main difference between ballistic and diffusive transport ? c) What are the main parameters that you need to change to ensure the electron transport is ballistic
F1 RDY RAY The figure above is a pin-joint frame with horizontal member length l = 3m and vertical member length h = 5m. (Note that the diagram is not to scale.) You are given that F = 48KN, RAY = 16KN and Rpy = 32kN. Use the method of sections to calculate the forces in members BC, FC and FE. Enter your answers in kilonewtons (kN) correct to 2 decimal places. Enter FBC : kN ype here to search
5
Fill up the blanks
Solve accurately
Based on the animation, Choose q1 = 2 µC; and q2 = 4 µC; using this q1q2 = 8 µC; use the simulation to find the force for the following distances and match the forces first 1. 10 cm = 0.1 m 2.9 cm = 0.09 m 3.8 cm = 0.08 m 4.7 cm = 0.07 m 5.6 cm = 0.06 m a. F12-F21 =7.190 N b. F12 F21 = 11.234 N c. F12 F21 = 14.674 N d. F12 F21 = 19.972 N e. F12 F21 =8.877 N 1. when q1 = 2 μC; and q2 = 4 μC and r=0.1 m 2. when q1 = 2 μC; and q2 = 4 µC and r =0.09 m 3. when q1 = 2 μC; and q2 = 4 µC and r =0.08 m 4. when q1 = 2 μC; and q2 = 4 μC and r = 0.07 m 5. when q1 = 2 μC; and q2 = 4 µC and r=0.07 m a a a 44 46 → →
For the following image V₁=65.9V, V₂=54.7V, and V3=43.5V. A proton's speed as it passes point A is 46115.0m/s and it follows the trajectory shown. What is the proton's speed at point B? A V₁ ¡B V2 V3
11
Two dots start at the orgin (0,0) coordinate system. Dot A move with the positive x-axis having a speed of 2m/s and dot B is moving along from the y-axis having a speed of 3m/s. How fast is the distance between the two dots changing when Dot A is 6m from (0,0)? Draw the diagram of the solution.
Given: 6 people masses:435 kg avg weight 1001b m= lo40kg per cart Cart 1= 3.4 mlong 5.other carts = 2.7m long Full length = 19.5m hç = All together m:6675 kg %3D Vi= 19.5m 6.68335 = v = Ax V, = 2.918 し- 19.5 Vs = 31.4 m/s ニ

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